 | Robert Simson - Trigonometry - 1781 - 534 pages
...let AB be the greater, and from it cut 'off DB equal to AC, . the lefs,and join DC. therefore becaufe in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two fides DB, BC are equal to the two AC, CB, each to each; and the angle DBC is... | |
 | Euclid, John Playfair - Euclid's Elements - 1795 - 462 pages
...AB be the greater, and from it cut a off DB equal to AC, the lefe, and join DC ; therefore, becaufe in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two fides DB, BC are equal to the two AC, CB, each to each ; but the angle DBC... | |
 | Alexander Ingram - Trigonometry - 1799 - 374 pages
...AB be the greater, and from it cut a off DB equal to AC, the lefs, and join DC ; therefore, becaufe in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two fides DB, BC are equal to the two AC, CB, each to each ; and the angle DBC... | |
 | Robert Simson - Trigonometry - 1804 - 530 pages
...the greater, and from it cut * oft'DB equal to AC, a. 3. x. the lefs, and join DC. therefore becaufe in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two fides DB, BC are equal to the two AC, CB, each to each ; and the angle DBC... | |
 | Robert Simson - Trigonometry - 1806 - 546 pages
...the greater, and from it cut a off DB a. 3. 1. equal to AC, the less, and join DC ; there- A fore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to to the two AC, CB, each to each ; and the angle DBC... | |
 | John Playfair - Mathematics - 1806 - 320 pages
...other : let AB be the greater, and from it cut* off DB equal to AC, the less, and join DC ; therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB, each to each ; but the angle DBC... | |
 | Euclides - 1816 - 588 pages
...be the greater ; and from it cut" • 3. 1. off DB equal to AC, the less, and join DC; therefore, , because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the twosides, DB, BC are equal to the two AC, CB each to each ; and the angle DBC is... | |
 | John Playfair - 1819 - 354 pages
...greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, be- * cause in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB, each to each ; but the angle DBC... | |
 | Peter Nicholson - Mathematics - 1825 - 1046 pages
...Let AB be the greater; and from it cut (3. 1.) off DB equal AC, the less, and join DC ; therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both the two sides, DB,BC, are equal to the two AC, CB each to each ; and the angle DBC is... | |
 | Robert Simson - Trigonometry - 1827 - 546 pages
...AB be the greater ; and * 3. 1. from it cut * off DB equal to AC, the less, and join DC : therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides, DB, BC are equal to the two AC, CB, each to ' 4. 1. each; and the angle... | |
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therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides, DB, BC are equal to the two AC, CB, each to each ; and the angle DBC is equal to... 
