| Robert Simson - Trigonometry - 1762 - 488 pages
...therefore AB is at right E / ^ angles b to the plane HGK. for the .s b. 8 .n. fame reafon, CD is likewife **at right — — —~angles to the plane HGK. therefore...each of them at right angles to the plane HGK. but** \f Wo ftraighl: lines be at right angles to the fame plane, they i\ill be parallel c to one another.... | |
| Robert Simson - Trigonometry - 1775 - 534 pages
.../ b 8l "' feme reafon, CDislikewifeat rii*ht r+ ..*rn angles to the plane HGK. ThtTre- w ^ ** fore **AB, CD are each of them at right angles to the plane HGK. But if two** ftraight lines be at right angles to the fame plane, they fliall be parallel c to one another. Therefore... | |
| Euclid - 1781 - 552 pages
...AB ; therefore AB is at right anglesb to the plane HGK. For the * a &f " famereafon, CD is likewife **at right angles to the plane HGK. Therefore AB, CD...them at right angles to the plane HGK. But if two** ftraight lines be at right angles to the fame plane, they fhall be parallel c to one another. Therefore... | |
| Robert Simson - Trigonometry - 1781 - 534 pages
...for the S^ b. 8. u. fame reafbn, CD is likewife at right ' angles to the plane HGK. therefore O 1\_ **AB, CD are each of them at right angles to the plane HGK. but if two** ftruight lines be at right angles to the fame plane, they faall be parallel c to one another. therefore... | |
| John Playfair - Euclid's Elements - 1795 - 462 pages
...therefore AB is at right angles b A IT „ to the plane HGK. For the fame reafon, CD . * . ib like wife **at right angles to the plane HGK. Therefore AB, CD...each of them at right angles to the plane HGK. But if** Book vil. E-F -I) uijauci JJVJAV. .iJLii. i* . -t» • '• , ••• . ^ tv.ollraight lines are... | |
| Alexander Ingram - Trigonometry - 1799 - 374 pages
...reafon, CD is "/ likewife at right angles to the plane _ £_ _ HGK. Therefore AB, CD are each £ K. D **of them at right angles to the plane HGK. But if two** ftraight lines be at right angles to the fame plane, they are parallel c; therefore f. 6. it. AB is... | |
| Robert Simson - Trigonometry - 1804 - 528 pages
...11. fame reafon, CD is likewife at right ~ .__ .r: angles to the plane HGK. therefore \+ Jx. • J.* **AB, CD are each of them at right angles to the plane HGK. but if two** ftraight lines be at right angles to the fame plane, they fhall be parallel c to one another. therefore... | |
| Robert Simson - Trigonometry - 1806 - 548 pages
...same reason, CD is likewise ^r at right angles to the plane HGK. r~ Therefore AB, CD are each of CK n **them at right angles to the plane HGK. But if two straight lines** be at right angles to the same plane, they shall be parallel6 to one another. Therefore AB is c 6.... | |
| Euclid - Geometry - 1810 - 554 pages
...and EF is parallel \ G to AB; therefore AB is at right \ ' p anglesb to the plane HGK. For /' be. 11. **the same reason, CD is likewise at right angles to...angles to the plane HGK. But if two straight lines** be at right angles to the same plane, they shall be parallel« to one another. Therefore AB isc6. 11.... | |
| Euclides - 1814 - 560 pages
...plane HGK. For the same reason, CD is likewise at right _ angles to the plane HGK. There-C KD fore **AB, CD, are each of them at right angles to the plane...lines are at right angles to the same plane, they** shall be parallel 0 to one another. There- • 6.11. fore AB is parallel to CD. Wherefore, two straight... | |
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