 | Charles Vyse - Arithmetic - 1785 - 350 pages
...continuing by the Increafc of 2 to 100 Places? PROPOSITION VII. The firft Term, common Difference, and Number of Terms being given, to find the Sum of all the Series. RULE. From tli? Product of the Number of Terms in the common Difference, fubtra'cl: the common... | |
 | Charles Vyse - Arithmetic - 1806 - 342 pages
...continuing by the Increase of 2 to 100 Places? PROPOSITION VII. The first Term, common Difference, and Number of Terms being given, to find the Sum of all the Series. RULE. From the Product of the Number of Terms in tl# common Difference, subtract the common... | |
 | Samuel Webber - Arithmetic - 1812 - 260 pages
...terms. 4. The common difference. 5. The sum of all the terms. PR0BLEM 1. Tke first term, the last term, and the number of terms being given, to find the sum of all the terms. RULE.* / Multiply the sum of the extremes by the number of terms, ami half the product will be die... | |
 | Charles Butler - Mathematics - 1814 - 540 pages
...be found, as is shewn by the rules and examples following. 289. The least term, the greatest term, and the number of terms, being given, to find the sum of all the terms. RULE. Add the least and greatest terms together, multiply the sum by half the number of terms, and... | |
 | Nathan Daboll - Arithmetic - 1815 - 250 pages
...first and last terms of which are culled the extremes.* PROBLEM I. The first term, the last term,.and the number of terms being given, to find the sum .of all the terms. *,:} series in progression includes Jive parts, viz. the, jfirsi term, last term, number of terms,... | |
 | Nathan Daboll - Arithmetic - 1817 - 252 pages
...terms of the progression ; the first u.,d last terms of which are cal,ed The first term, the last term, and the number of terms being given, to find the sum of all the terms. *A series in progression includes Jive parts, rz'z. the first term, last term, number of terms, common... | |
 | Daniel Staniford - Arithmetic - 1818 - 332 pages
...com. ditt'. of their ages. Youngest 21 4th . . 14' 7lh . 6th ... 5th . . 11 J PROPORTION II. The two extremes and the number of terms being given, to find the sum of all the terms. RULE. Multiply the sum of the two extremes by half the number of terms, the prodnct will be the sum... | |
 | George G. Carey - Arithmetic - 1818 - 602 pages
...three of face being given, the other two may l»e foiled. st: L THE LEAST TERM, THE GREATEST TERM, AND THE NUMBER OF TERMS BEING GIVEN, TO FIND THE SUM OF ALL THE TERMS. RULE. Multiply the sum *f tbe greatest a*4 least terns by half the number of tersw, or by tbe whole... | |
 | Arithmetic - 1818 - 264 pages
...terms. 4. The comtnpn difference. 5. The sum of all the terms. PROBLEM I. The first term, the last term, and the number of terms being given, to find the sum of all the terms. RULE. Multiply the sum of the extremes by the number of terms,," and half the product will be the answer.... | |
 | James Maginness - Arithmetic - 1821 - 378 pages
...common difference? By formula 1, per table, 3JL=3 = 2. Ans. PROBLEM 2. The first term, the last term, and the number of terms, being given, to find the sum of all the terms. The extremes of an arithmetical series are 3 and 39, and the number of terms 19; required, the sum... | |
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PROBLEM I. The first term, the last term, and the number of terms being given, to find the sum of all the terms. 
