## Euclidian Geometry |

### From inside the book

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Page xvi

... , for divides read divide . ,, 129 ,,, 1 , add if possible , let them

... , for divides read divide . ,, 129 ,,, 1 , add if possible , let them

**bisect**each other ; IZI ,,, 13 , omit to it . " " " 201. In the diagram the diagonal of FB is AC . M PLANE GEOMETRY . BOOK I. INTRODUCTION . A point xvi. Page 11

... the centre of the ACE , BCD , .. AB is AC , .. AB is = BC , .. AC is BC ; = .. ABC is an equilateral triangle , and it has been described upon AB . Q. E. F. PROBLEM B. To

... the centre of the ACE , BCD , .. AB is AC , .. AB is = BC , .. AC is BC ; = .. ABC is an equilateral triangle , and it has been described upon AB . Q. E. F. PROBLEM B. To

**bisect**a given angle . D E STRAIGHT LINES , ANGLES AND TRIANGLES . Page 12

Francis Cuthbertson (M.A.). PROBLEM B. To

Francis Cuthbertson (M.A.). PROBLEM B. To

**bisect**a given angle . D E Let DAE be the given angle . It is required to**bisect**it . With centre A describe a circle cutting AD , AE in the points B and C. With centres B and C describe equal ... Page 13

Francis Cuthbertson (M.A.). PROBLEM C. To

Francis Cuthbertson (M.A.). PROBLEM C. To

**bisect**a given straight line . Let AB be the given straight line . It is required to**bisect**it . With centres A and B describe two circles having equal radii intersecting in C , D. Join CD ... Page 22

...

...

**Bisect**AC in E ; join BE and produce BE to F , making EF BE . = Join CF. Then , AE , EB are respectively = CE , EF , and AEB is = CEF ; L .. the LEAB is the ECF . = But the ACD is > the ECF ; .. LACD is > the EAB ; i.e. △ CAB . ( 1. 6 ) ...### Other editions - View all

### Common terms and phrases

applied base bisect Cambridge centre chapter chord circle circumference cloth College common complete contained Crown 8vo DEFINITION describe diameter difference divided double draw drawn Edition elementary English equal equiangular Examination Examples extremities fall fcap figure Find former four GEOMETRY given point given straight line Grammar greater Hence illustrations impossible inscribed introduction Join language Latin less magnitudes Master Mathematical meet method Notes opposite parallel parallelogram pass perpendicular plane polygon possible present principles PROBLEM produced Professor proportional PROPOSITION prove ratio reader rect rectangle rectilineal respectively revised right angles Schools Second Edition segment selected sides similar Similarly square taken tangent THEOREM third touch TREATISE triangle twice University volume whole