| Thomas Keith - Arithmetic - 1822 - 354 pages
...better methods. Thus, the square root of the square root=the biquadrate, or fourth rest, for £x|=«> The cube root of the square root, or the square root of the cube root «=*he sixth root, for |x!_s- The square root of the fourth root= the eighth root, for |xj=|, or £x$xi={-... | |
| Thomas Keith - Arithmetic - 1825 - 360 pages
...better methods. Thus, the square root of the square rw>t=the biquadrate, or fourth root, for |xi=iThe cube root of the square root, or the square root of the cube root —the sixth root, for {x J=J. The square root of the fourth root= the eighth root, for ixj=|, or *x^X... | |
| Frederick Emerson - Arithmetic - 1834 - 300 pages
...fourth power, and then the square root of that square root will be the fourth root. The sixth root is the cube root of the square root, or the square root of the cube root; because 3 X2 = 6. The eighth root is the square root of the square root of the square root; because... | |
| Frederick Emerson - Arithmetic - 1839 - 300 pages
...fourth power, and then the square root of that square root will be the fourth root. The sixth root is the cube root of the square root, or the square root of the cube root; because 3 X2— 6. The eighth roct is the square root of the square root of the square root; because... | |
| Roswell Chamberlain Smith - Arithmetic - 1841 - 324 pages
...of indices. 3. Thus the 4th root (2x2) = the square root of the square root ; the sixth root (3x2) = the cube root of the square root, or the square root of the cube root. 4. The 8th root (2x2x2) = the square root of the square root ol the square root ; the ninth root (3x3)... | |
| Roswell Chamberlain Smith - Arithmetic - 1842 - 320 pages
...of indices. 3. Thus the 4th root (2x2) = the square root of the square root ; the sixth root (3x2) = the cube root of the square root, or the square root of the cube root. 4. The 8th root (2x2x2) = the square root of the square root ot the square root ; the ninth root (3x3)... | |
| Roswell Chamberlain Smith - Arithmetic - 1843 - 320 pages
...of indices. 3. Thus the 4th root (2x2) = the square root of the square root; the sixth root (3x2) = the cube root of the square root, or the square root of the cube root. 4. The 8th root (2x2x2) = the square root of the square root ol the square root; the ninth root (3x3)... | |
| Roswell Chamberlain Smith - Arithmetic - 1850 - 314 pages
...of indices. 3. Thus the 4th root (2x2) = the square root of the square root; the sixth root (3x2) = the cube root of the square root, or the square root of the cube root. 4. The 8th root (2x2x2) = the square root of the square root ot the square root ; the ninth root (3x3)... | |
| James B. Dodd - Arithmetic - 1850 - 278 pages
...256 being thus equal to 4X4X4X 4, the 4th root of 256 is 4. In like manner, the 6th root is equal to the cube root of the square root, or the square root of the cube root ; and so on. Note. In common Arithmetic we seldom or never have occasion to employ any other than the... | |
| James B. Dodd - Arithmetic - 1852 - 410 pages
...factors, and then such root of that root as is denoted by the other factor. The 6th root is equal to the cube root of the square root, or the square root of the cube root, — the fraction £, which is the exponent of the 6th root, being equal to | The 5th root cannot be... | |
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