 30. A straight line drawn from the vertex of an isosceles triangle to the middle of the base is perpendicular to the base. Find the area of a regular pentagon whose sides are 24", if the radius of the circle drawn around the  Book III - Page 223by George William Myers - 1908Full view - About this book
 | Thomas Keith - Navigation - 1810 - 478 pages
...II. Hence every equilateral triangle is likewise equiangular, and the contrary. (I) COROLLARY III. A line drawn from the vertex of an isosceles triangle...middle of the base, is perpendicular to, the base. (K) COROLLARY IV. A perpendicular drawn from the vertex 'cf an isosceles triangle upon the base, always... | |
 | Adrien Marie Legendre - Geometry - 1819 - 574 pages
...the angle BAD = DAC, and that the angle EDA = ADC ; therefore these two last are right angles. Hence a straight line drawn from the vertex of an isosceles...triangle, to the middle of the base, is perpendicular to that base, anil divides the vertical angle into two equal parts. In a triangle that is not isosceles,... | |
 | Peter Nicholson - Architecture - 1823 - 210 pages
...angle C. 61. COROLLARY 1.—Hence every equilateral triangle is also equiangular. 62. COROLLARY 2.—A straight line drawn from the vertex of an isosceles triangle to the middle of the base will bisect the vertical angle, and be perpendicular to the base. THEOREM 12. 63. If two angles of... | |
 | Adrien Marie Legendre - 1825 - 570 pages
...the angle BAD = DAC, and that the angle EDA = ADC; therefore these two last are right angles. Henct a straight line drawn from the vertex of an isosceles...triangle, to the. middle of the base, is perpendicular to that base, and divides the vertical angle into two equal parts. In a triangle that is not isosceles,... | |
 | Adrien Marie Legendre, John Farrar - Geometry - 1825 - 280 pages
...the angle BAD = DAC, and that the angle BDA. = ADC; therefore these two last are right angles. Hence a straight line drawn from the vertex of an isosceles...to the •middle of the base, is perpendicular to that base, and divides the vertical angle into two equal parts. In a triangle that is not isosceles,... | |
 | Adrien Marie Legendre, John Farrar - Geometry - 1825 - 294 pages
...the angle BAD = DAC, and that the angle BDA = ADC; therefore these two last are right angles. Hence a straight line drawn from the vertex of an isosceles...triangle, to the middle of the base, is perpendicular to that base, and divides the vertical angle into two equal parts. In a triangle that is not isosceles,... | |
 | Thomas Keith - Navigation - 1826 - 504 pages
...II. Hence every equilateral triangle is likewise equiangular, and the contrary. (I) COROLLARY III. A line drawn from the vertex of an isosceles triangle...middle of the base, is perpendicular to the base. For the two sides FB and EC are equal to the two sides FA and AC, and the angle FBC is equal to the... | |
 | James Hayward - Geometry - 1829 - 218 pages
...perpendicular. PC, AB, AC ; PB and PC will be equal (41), and AB and AC will therefore be equal; and AG will be a straight line drawn from the vertex of an isosceles triangle to the middle of the base; that is—BC is perpendicular to the oblique line AG, when it is perpendicular to the straight line... | |
 | James Hayward - Geometry - 1829 - 228 pages
...PB, PC, AB, AC ; PB and PC will be equal (41), and AB and AC will therefore be equal ; and AG will be a straight line drawn from the vertex of an isosceles triangle to the middle of the base; that is—BC is perpendicular to the oblique line AG, w/icn it is perpendicular to the straight line... | |
 | Adrien Marie Legendre - Geometry - 1836 - 394 pages
...the angle BAD, is equal to DAC, and BDA to ADC, hence the latter two are right angles; therefore, the line drawn from the vertex of an isosceles triangle to the middle point of its base, is perpendicular to the base, and divides the angle at the vertex into two equal... | |
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