AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because A in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB. each to each ; and the angle... Euclid's Elements: Or, Second Lessons in Geometry,in the Order of Simson's ... - Page 13by Dennis M'Curdy - 1846 - 138 pagesFull view - About this book
| Robert Simson - Trigonometry - 1762 - 466 pages
...therefore becaufe in the triangles DBC, ACB, DB is equal to AC, and 1>C common to bath, the two fides **DB, BC are equal to the two AC, CB, each to each ; and the** angle DBC is equal to the ang'c ^CB ; therefore the bafe DC is equal to the bafe AB, and the triangle... | |
| Robert Simson - Trigonometry - 1775 - 520 pages
...therefore, becaufe in the triangles DBC, ACBi D3 is equal to AC, and BC common to both, the two fides **DB, BC are equal to the two AC, CB, each to each ; and the** angle DBC is equal to the angle ACB ; therefore the bale DC is eqtial to the bafe AB, and the triangle... | |
| Euclid - 1781 - 550 pages
...therefore, becaule in the triangles DBC, ACB, 1 >I> it equal to AC, and BC common to both, the two fides **DB, BC are equal to the two AC, CB, each to each ; and the** angle DBC is equal to the angle ACB ; therefore the bafe DC is equal to the bare AB, and the triangle... | |
| Euclid, James Williamson - Euclid's Elements - 1781 - 324 pages
...Jlraight line DB is equat to theJlraight line AC, but the Jlralght line BC common; certainly the two **DB, BC are equal to the two AC, CB, each to each; and** an angle, the angle contained by DBC is equal to the angle contained by ACB (by fupp,); wherefore (by... | |
| Robert Simson - Trigonometry - 1781 - 466 pages
...let AB be the greater, and from it cut 'off DB equal to AC, . the lefs,and join DC. therefore becaufe **in the triangles DBC, ACB, DB is equal to AC, and BC** common to both, the two fides DB, BC are equal to the two AC, CB, each to each; and the angle DBC is... | |
| John Playfair - Trigonometry - 1795 - 444 pages
...AB be the greater, and from it cut a off DB equal to AC, the lefe, and join DC ; therefore, becaufe **in the triangles DBC, ACB, DB is equal to AC, and BC** common to both, the two fides DB, BC are equal to the two AC, CB, each to each ; but the angle DBC... | |
| Alexander Ingram - Trigonometry - 1799 - 351 pages
...AB be the greater, and from it cut a off DB equal to AC, the lefs, and join DC ; therefore, becaufe **in the triangles DBC, ACB, DB is equal to AC, and BC** common to both, the two fides DB, BC are equal to the two AC, CB, each to each ; and the angle DBC... | |
| Robert Simson - Trigonometry - 1804
...the greater, and from it cut * oft'DB equal to AC, a. 3. x. the lefs, and join DC. therefore becaufe **in the triangles DBC, ACB, DB is equal to AC, and BC** common to both, the two fides DB, BC are equal to the two AC, CB, each to each ; and the angle DBC... | |
| Robert Simson - Trigonometry - 1806 - 518 pages
...the greater, and from it cut a off DB a. 3. 1. equal to AC, the less, and join DC ; there- A fore, **because in the triangles DBC, ACB, DB is equal to AC, and BC** common to both, the two sides DB, BC are equal to to the two AC, CB, each to each ; and the angle DBC... | |
| John Playfair - Euclid's Elements - 1806 - 320 pages
...other : let AB be the greater, and from it cut* off DB equal to AC, the less, and join DC ; therefore, **because in the triangles DBC, ACB, DB is equal to AC, and BC** common to both, the two sides DB, BC are equal to the two AC, CB, each to each ; but the angle DBC... | |
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