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" AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because A in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB. each to each ; and the angle... "
Euclid's Elements: Or, Second Lessons in Geometry,in the Order of Simson's ... - Page 13
by Dennis M'Curdy - 1846 - 138 pages
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The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ...

Robert Simson - Trigonometry - 1762 - 466 pages
...therefore becaufe in the triangles DBC, ACB, DB is equal to AC, and 1>C common to bath, the two fides DB, BC are equal to the two AC, CB, each to each ; and the angle DBC is equal to the ang'c ^CB ; therefore the bafe DC is equal to the bafe AB, and the triangle...
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The Elements of Euclid, Viz: The Errors, by which Theon, Or Others, Have ...

Robert Simson - Trigonometry - 1775 - 520 pages
...therefore, becaufe in the triangles DBC, ACBi D3 is equal to AC, and BC common to both, the two fides DB, BC are equal to the two AC, CB, each to each ; and the angle DBC is equal to the angle ACB ; therefore the bale DC is eqtial to the bafe AB, and the triangle...
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The First Six Books: Together with the Eleventh and Twelfth

Euclid - 1781 - 540 pages
...therefore, becaule in the triangles DBC, ACB, 1 >I> it equal to AC, and BC common to both, the two fides DB, BC are equal to the two AC, CB, each to each ; and the angle DBC is equal to the angle ACB ; therefore the bafe DC is equal to the bare AB, and the triangle...
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The Elements of Euclid: With Dissertations Intended to Assist and Encourage ...

Euclid, James Williamson - Euclid's Elements - 1781 - 309 pages
...Jlraight line DB is equat to theJlraight line AC, but the Jlralght line BC common; certainly the two DB, BC are equal to the two AC, CB, each to each; and an angle, the angle contained by DBC is equal to the angle contained by ACB (by fupp,); wherefore (by...
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The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ...

Robert Simson - Trigonometry - 1781 - 466 pages
...let AB be the greater, and from it cut 'off DB equal to AC, . the lefs,and join DC. therefore becaufe in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two fides DB, BC are equal to the two AC, CB, each to each; and the angle DBC is...
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Elements of Geometry;: Containing the First Six Books of Euclid, with Two ...

John Playfair - Euclid's Elements - 1795 - 444 pages
...AB be the greater, and from it cut a off DB equal to AC, the lefe, and join DC ; therefore, becaufe in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two fides DB, BC are equal to the two AC, CB, each to each ; but the angle DBC...
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The Elements of Euclid: Viz. the First Six Books, with the Eleventh and ...

Alexander Ingram - Trigonometry - 1799 - 351 pages
...AB be the greater, and from it cut a off DB equal to AC, the lefs, and join DC ; therefore, becaufe in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two fides DB, BC are equal to the two AC, CB, each to each ; and the angle DBC...
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The Elements of Euclid: Also the Book of Euclid's Data ...cor. viz. The ...

Robert Simson - Trigonometry - 1804
...the greater, and from it cut * oft'DB equal to AC, a. 3. x. the lefs, and join DC. therefore becaufe in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two fides DB, BC are equal to the two AC, CB, each to each ; and the angle DBC...
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The Elements of Euclid: The Errors, by which Theon, Or Others, Have Long Ago ...

Robert Simson - Trigonometry - 1806 - 518 pages
...the greater, and from it cut a off DB a. 3. 1. equal to AC, the less, and join DC ; there- A fore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to to the two AC, CB, each to each ; and the angle DBC...
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Elements of Geometry: Containing the First Six Books of Euclid, with a ...

John Playfair - Euclid's Elements - 1806 - 311 pages
...other : let AB be the greater, and from it cut* off DB equal to AC, the less, and join DC ; therefore, because in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB, each to each ; but the angle DBC...
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