Euclid's Elements: Or, Second Lessons in Geometry,in the Order of Simson's and Playfair's Editions ... |
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Page 8
... parallelogram is that straight line which joins opposite angles . 17. A semicircle is a figure contained by the diameter and half the circumference . 18. An arc is any part of the circumference of a circle , a chord is the straight line ...
... parallelogram is that straight line which joins opposite angles . 17. A semicircle is a figure contained by the diameter and half the circumference . 18. An arc is any part of the circumference of a circle , a chord is the straight line ...
Page 24
... BD . Wherefore , the straight lines which join , & c . Recite ( a ) pos 1 ; ( b ) p . 27 ; ( c ) p . 4 . A B C D. Q. E. D. Definition . A parallelogram is a quadrilateral figure whose oppo- 24 [ BOOK 1 . SECOND LESSONS IN GEOMETRY .
... BD . Wherefore , the straight lines which join , & c . Recite ( a ) pos 1 ; ( b ) p . 27 ; ( c ) p . 4 . A B C D. Q. E. D. Definition . A parallelogram is a quadrilateral figure whose oppo- 24 [ BOOK 1 . SECOND LESSONS IN GEOMETRY .
Page 25
... parallelogram are equal , and the diameter bisects it ( a ) . Because ABCD is a parallelogram , its opposite sides are parallel ( 6 ) ; and because BC joins opposite angles ( c ) it meets the parallels AB , CD , and also the ...
... parallelogram are equal , and the diameter bisects it ( a ) . Because ABCD is a parallelogram , its opposite sides are parallel ( 6 ) ; and because BC joins opposite angles ( c ) it meets the parallels AB , CD , and also the ...
Page 26
... parallelogram , and equal to ABCD ; - because they are upon the same base BC , and between the same par- allels BC , AH ( c ) . For the like reason , EFGH is equal to EBCH ; hence ABCD equals EFGH ( d ) . Wherefore , parallelograms ...
... parallelogram , and equal to ABCD ; - because they are upon the same base BC , and between the same par- allels BC , AH ( c ) . For the like reason , EFGH is equal to EBCH ; hence ABCD equals EFGH ( d ) . Wherefore , parallelograms ...
Page 27
... parallelogram ( ABCD ) , and a triangle ( EBC ) , be upon the same base BC , and between the same parallels ( BC , AE ) , the parallelogram is double of the tri- angle . Join AC ; then the triangle ABC equals the tri- BOOK I. ] 27 ...
... parallelogram ( ABCD ) , and a triangle ( EBC ) , be upon the same base BC , and between the same parallels ( BC , AE ) , the parallelogram is double of the tri- angle . Join AC ; then the triangle ABC equals the tri- BOOK I. ] 27 ...
Other editions - View all
Euclid's Elements, Or Second Lessons in Geometry, in the Order of Simson's ... D. M'Curdy No preview available - 2017 |
Euclid's Elements, Or Second Lessons in Geometry, in the Order of Simson's ... D. M'Curdy No preview available - 2017 |
Common terms and phrases
ABCD alternate angles angle ACD angles ABC angles equal antecedents Argument base BC bisected centre Chart chord circle ABC circumference Constr Denison Olmsted diameter draw drawn equal angles equal arcs equal radii equal sides equals the squares equiangular equilateral equilateral polygon equimultiples exterior angle fore Geometry given circle given rectilineal given straight line given triangle gles gnomon greater inscribed isosceles isosceles triangle join less meet multiple opposite angles parallelogram parallelopipeds pentagon perimeter perpendicular plane polygon produced propositions Q. E. D. Recite radius ratio rectangle rectangle contained rectilineal figure School secant segment semicircle similar sine square of AC tangent third touches the circle triangle ABC unequal Wherefore
Popular passages
Page 90 - If two triangles have one angle of the one equal to one angle of the other, and the sides about the equal angles proportionals, the triangles shall be equiangular, and shall have those angles equal which are opposite to the homologous sides.
Page 117 - In the same way it may be proved that a : b : : sin. A : sin. B, and these two proportions may be written a : 6 : c : : sin. A : sin. B : sin. C. THEOREM III. t8. In any plane triangle, the sum of any two sides is to their difference as the tangent of half the sum of the opposite angles is to the tangent of half their difference. By Theorem II. we have a : b : : sin. A : sin. B.
Page 92 - IN a right-angled triangle, if a perpendicular be drawn from the right angle to the base, the triangles on each side of it are similar to the whole triangle, and to one another.
Page 79 - THEOREM. lf the first has to the second the same ratio which the third has to the fourth, but the third to the fourth, a greater ratio than the fifth has to the sixth ; the first shall also have to the second a greater ratio than the fifth, has to the sixth.
Page 87 - If a straight line be drawn parallel to one of the sides of a triangle, it shall cut the other sides, or those sides produced, proportionally...
Page 26 - Triangles upon equal bases, and between the same parallels, are equal to one another.
Page 94 - Equal parallelograms which have one angle of the one equal to one angle of the other, have their sides about the equal angles reciprocally proportional ; and parallelograms that have one angle of the one equal to one angle of the other, and their sides about the equal angles reciprocally proportional, are equal to one another.
Page 12 - THE angles at the base of an isosceles triangle are equal to one another : and, if the equal sides be produced, the angles upon the other side of the base shall be equal.
Page 133 - If a straight line stand at right angles to each of two straight lines at the point of their intersection, it shall also be at right angles to the plane which passes through them, that is, to the plane in which they are.
Page 13 - AB be the greater, and from it cut (3. 1.) off DB equal to AC the less, and join DC ; therefore, because A in the triangles DBC, ACB, DB is equal to AC, and BC common to both, the two sides DB, BC are equal to the two AC, CB. each to each ; and the angle DBC is equal to the angle ACB; therefore the base DC is equal to the base AB, and the triangle DBC is< equal to the triangle (4. 1.) ACB, the less to 'the greater; which is absurd.