 The equation ad = be gives a — -£, b = — ; so that an d с extreme may be found by dividing the product of the means by the other extreme ; and a mean may be found by dividing the product of the extremes by the other mean.  A College Algebra - Page 155by George Albert Wentworth - 1888 - 494 pagesFull view - About this book
 | Etienne Bézout - Mathematics - 1824 - 238 pages
...second by the third and dividing their product by the first. For it is plain (174) the fourth term may be found by dividing the product of the extremes by the first term. But this product is the same as the prod net of the means. Then the fourth term may also... | |
 | George Peacock - Algebra - 1830 - 732 pages
...proportion may be found by dividing the product of the means by the other extreme ; and either of the means may be found by dividing the product of the extremes by the other mean. 387- In order to arrange the quantities in the question, mcnt ^"thc in the proportion which is necessary... | |
 | Benjamin Greenleaf - Arithmetic - 1849 - 336 pages
...18 and 7, thus 14 X 9 = 18 X 7. ART. 24*». If the extremes and one of the means are given the other mean may be found by dividing the product of the extremes by the given mean. Thus, if the extremes are 3 and 24, and the given mean 6, the other mean is 12 ; because... | |
 | J L. Ellenberger - 1854 - 338 pages
...extremes is found by dividing the product of the means by the other extreme, and one of the means is found by dividing the product of the extremes by the other mean. 346 Now, the four terms of a geometrical proportion may be transposed in several ways, without altering... | |
 | Benjamin Greenleaf - Arithmetic - 1857 - 452 pages
...and 20 ; thus, 16 X 10 = 8 X 20. Hence, 1. If the extremes and one of the means are given, the other mean may be found by dividing the product of the extremes by the given mean ; or, 2. If the means and one of the extremes are given, the other extreme may be found... | |
 | Benjamin Greenleaf - Arithmetic - 1857 - 336 pages
...compare with that of the means ? ART. 242. If the extremes and one of the means are given, the other mean may be found by dividing the product of the extremes by the given mean. Thus, if the extremes are 3 and 24, and the given mean 6, the other mean is 12 ; because... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 456 pages
...and 20 ; thus, 16 X 10 = 8 X 20. Hence, 1. If the extremes and one of the means are given, the other mean may be found by dividing the product of the extremes by the given mean ; or, 2. If the means and one of the extremes are given, the other extreme may be found... | |
 | Benjamin Greenleaf - Arithmetic - 1858 - 458 pages
...and 20; thus, 16 X 10 — 8 X 20. Hence, 1. If the extremes and one of the means are given, the other mean may be found by dividing the product of the extremes by the given mean ; or, 2. If the means and one of the extremes are given, the other extreme may be found... | |
 | John Box (of London.) - 1861 - 138 pages
...of the means will equal the product of the extremes 5 x 40 = 20 x 10, and that either of tho means may be found by dividing the product of the extremes by the other mean, and either of the extremes be found by dividing the product of the means by the other extreme. 143.... | |
 | George Augustus Walton - Arithmetic - 1864 - 364 pages
...found by dividing the product of the means by the given extreme ; and whenever a mean is wanting, it may be found by dividing the product of the extremes by the given mean. Supply the terms wanting in the following proportions : — 1. 5:1 = 50:? 2. 8 : ? = 3... | |
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