| Thomas Leybourn - Mathematics - 1814 - 420 pages
...Hence, by adopting the notation in the question, we have But the sum of the angles of any polygon being **equal to twice as many right angles as the polygon has sides,** less four; the sum of all the angles of the polygon will be equal to an even number of right angles,... | |
| John Radford Young - Euclid's Elements - 1827 - 228 pages
...to say, the sum of the angles of the polygon, together with those about the point within . it, are **equal to twice as many right angles as the polygon has sides** ; but those angles which are' about the point, amount to four right angles, (Prop. VI. Cor. 2.) deducting... | |
| Adrien Marie Legendre - Geometry - 1836 - 394 pages
...each as there are sides of the polygon : hence, the sum of all the interior and exterior angles is **equal to twice as many right angles as the polygon has sides.** Again> the sum of all the interior . angles is equal to two.right angles, taken as many times, less... | |
| William Scott - Measurement - 1845 - 288 pages
...and end ought to coincide. Also, the sum of all the angles, together with four right angles, ought to **be equal to twice as many right angles as the polygon has sides** (Eue. i. 32. cor.). To find the angle contained by two straight lines conceived to be drawn from a... | |
| Nathan Scholfield - 1845 - 894 pages
...figure has sides, wanting four right angles. Hence, the interior angles plus four right angles, is **equal to twice as many right angles as the polygon has sides,** and consequently, equal to the sum of the interior angles plus the exterior angles. Taking from each... | |
| Sir J. Butler Williams - Geodesy - 1846 - 368 pages
...sum of all the interior angles of the polygon formed by joining the stations by straight lines will **be equal to twice as many right angles as the polygon has sides,** wanting 4 right angles (Euc. Cor. 32, I.) Thus, if the figure have 3 sides, the sum of the interior... | |
| George Roberts Perkins - Geometry - 1847 - 326 pages
...angles is equal to four right angles (Prop. xxm) ; therefore the sum of all the interior angles is **equal to twice as many right angles as the polygon has sides,** wanting four right angles. Cor. 1. Jn any triangle, the sum of all the three angles is equal to two... | |
| Elias Loomis - Conic sections - 1849 - 252 pages
...equal to two right angles (Prop. XXVII.); therefore the sum of the angles of all the triangles, is **equal to twice as many right angles as the polygon has sides.** But the same angles are equal to the angles of the polygon, together with the angles at the point F,... | |
| Charles Davies - Trigonometry - 1849 - 372 pages
...each as there are sides of the polygon : hence, the sum of all the interior and exterior angles is **equal to twice as many right angles as the polygon has sides.** Again, the sum of all tho interior angles is equal to two right angles, taken as many times, less two,... | |
| Charles Davies - Geometry - 1850 - 238 pages
...each as there are sides of the polygon : hence, the sum of all the interior and exterior angles will **be equal to twice as many right angles as the polygon has sides.** But the sum of all the interior angles together with four right angles, is equal to twice as many right... | |
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