 | Jeremiah Day - Algebra - 1814 - 304 pages
...will be equal to , 2Q—X. Prob. 4. Divide 48 into two such parts, thafc if the less be divided by A and the greater by 6, the sum of the quotients will be 9. , Here if x be put for the smaller part, the greater will be48-*. x 48 — x By the conditions of the... | |
 | Jeremiah Day - Algebra - 1820 - 352 pages
...other will be equal to 20 — x. Prob. 4. Divide 48 into two such parts, that if the less be divided by 4, and the greater by 6, the sum of the quotients will be 9. Here, if x be put for the smaller part, the greater will be 48— x. x 48— x By the conditions of... | |
 | Jeremiah Day - Algebra - 1827 - 352 pages
...other will be equal to 20 - x. Prob. 4. Divide 48 into two such parts, that if the less be divided by 4, and the greater by 6, the sum of the quotients will be 9. Here, if x be put for the smaller part, the greater will be 48— x. By the conditions of the problem-^—... | |
 | James Bates Thomson - Algebra - 1844 - 272 pages
...is the value of the estate 1 Prob. 4. Divide 48 into two such parts, that if the less be divided by 4, and the greater by (6, the sum of the quotients will be 9. Let x = the smaller part. Then 48 — x = the greater part. By the conditions of the problem, - -f... | |
 | Horatio Nelson Robinson - Algebra - 1844 - 184 pages
...can as well be dispensed with. PROB. 8. Divide 48 into two such parts, that if the less be divided by 4, and the greater by 6, the sum of the quotients will be 9. (D. 77.) Ans. 12 the less. Let z=the less ; then 48 — z=the greater. x , 48— x 4+~6-=9Multiply... | |
 | Horatio Nelson Robinson - Algebra - 1846 - 276 pages
...each? Ans. Chaise $120. Horse $80. 10. Divide 48 into two such parts, that if the less be divided by 4, and the greater by 6, the sum of the quotients...following manner : The first is to have $200 more than 1 of the whole. The second is to have $340 more than ^ of the whole The third is to have $300 more... | |
 | James Bates Thomson - Algebra - 1846 - 276 pages
...is the value of the estate 1 Prob. 4. Divide 48 into two such parts, that if the less he divided by 4, and the greater by 6, the sum of the quotients will he 9. Let x = the smaller part. Then 48- — a; = the greater part. rf* AQ /p By the conditions of... | |
 | Jeremiah Day - Algebra - 1847 - 358 pages
...other will be equal to 20 - x. Prob. 4. Divide 48 into two such parts, that if the less be divided by 4, and the greater by 6, the sum of the quotients will be 9. Here, if a; be put for the smaller part, the greater will be 48-*. By the conditions of the problem... | |
 | Jeremiah Day, James Bates Thomson - Algebra - 1848 - 264 pages
...is the value of the estate 1 Prob. 4. Divide 48 into two such parts, that if the less be divided by 4, and the greater by 6, the sum of the quotients will be 9. Let x -. the smaller part. Then 48 — x = the greater part. y, AU £1 By the conditions of the problem,... | |
 | Horatio Nelson Robinson - Algebra - 1850 - 256 pages
...done), by laborious multiplication. t 8. Divide 48 into two such parts, that if the less be divided by 4, and the greater by 6, the sum of the Quotients will be 9. Ans. 12 and 36. 9. A clerk spends *• of his salary for his board, and f of the remainder in clothes, and yet saves... | |
| |
Divide 48 into two such parts, that if the less be divided by 4, and the greater by 6, the sum of the quotients will be 9. Ans. 12 and 36. 
