# Practical Work in General Physics for Use in Schools and Colleges

Clarendon Press, 1894 - Physics - 83 pages
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Page 33 - Or in different words, the specific gravity of a body is the ratio of its mass to the mass of an equal volume of a standard substance.
Page 22 - The area of the entire surface of a cylinder is equal to the product of the circumference of the base by the sum of the altitude and the radius of the base (684).
Page 81 - PROBLEM 2. — To draw a perpendicular to a straight line from a given point in that line.
Page 33 - ... In the case of gases, the liter, = 1000 cc., is taken as the unit of volume, and the mass of one liter of normal hydrogen, called a crith, = .0896 gram, is taken as the unit of mass. The density of a gas, then, is the number of criths contained in one liter of it, measured at 0° C. and 760 mm.; or the number of times it is heavier than an equal volume of hydrogen. Hence the mass in grams of a liter of any normal gas can be found by multiplying its density by .0896. EXAMPLE. The density of carbon...
Page 78 - W = the weight of a volume of water equal to the volume of the solid, and SP- Gr- = EXAMPLE.
Page xii - He proved also the relation between the length of a pendulum and its time of swing, and dealt with circular motion.
Page 18 - ... area, equal to the rectangle of the same base and altitude ; for, if the oblique or triangular portion be cut from one end and added to the other, the figure becomes a rectangle ; and as the area of a rectangle is equal to the product of the number of units in its base and altitude, it follows that the area of any triangle is equal to half the product of its length and breadth. This, then, may be adopted as an element into which all plane figures can be divided, and their component areas made...
Page 14 - The ratio of the length of the circumference of a circle to its diameter is usually denoted in works on mathematics and mechanics by the Greek letter n- (pronounced like the English word 'pie'), and is 3 . 14159 .... This number is 'incommensurable,' which means that it cannot be expressed exactly in our ordinary system of numeration.
Page 1 - MEASURE. 10 millimetres = 1 centimetre. 10 centimetres = 1 decimetre. 10 decimetres = 1 metre. 10 metres = 1 decametre. 10 decametres = 1 hectometre. 10 hectometres = 1 kilometre. 10 kilometres = 1 myriametre.
Page 28 - To prove that the volume of a sphere is equal to two-thirds of the volume of the circumscribing cylinder.