| Augustus De Morgan - 1831 - 108 pages
...exponent of c. Thus c>xc3 = c7. To divide a term of the second series by one which comes before it, subtract the exponent of the divisor from the exponent of the dividend, and make this difference the exponent of c. Thus, c1 -> = <?' c4 These rules are intelligible for all... | |
| Frederick Emerson - Arithmetic - 1834 - 300 pages
...power; as 23 X 23 X 23 = 29. Division being the reverse of multiplication, it is evident, that if we subtract the exponent of the divisor from the exponent of the dividend, the remainder is the exponent of the quotient. For example, if we divide the fifth power by the third... | |
| Mathematics - 1836 - 352 pages
...exponent of c. Thus c4xc3 = c7. To divide a term of the second series by one which comes before it, subtract the exponent of the divisor from the exponent of the dividend, and make this difference the exponent of c. Thus26 These rules are intelligible for all terms of the... | |
| Frederick Emerson - Arithmetic - 1839 - 300 pages
...power; as 23 X 23 X 23 = 29. Division being the reverse of multiplication, it is evident, that if we subtract the exponent of the divisor from the exponent of the dividend, the remainder is the exponent of the quotient. For example, if we divide the fifth power by the third... | |
| John H. Harney - Algebra - 1840 - 298 pages
...quotient of a2 by a? a4 by tfi? ai6 by aV2? In order to obtain the quotient of one power of a by another, subtract the exponent of the divisor from the exponent of the dividend. The remainder is the exponent of a in the quotient. 3. Divide a4 by a Лпз. ať. 4. a8 by a2 5. aз... | |
| Ebenezer Bailey - Algebra - 1840 - 270 pages
...required to divide a power of any letter, as a5, by another power of the same letter, as a3, we must subtract the exponent of the divisor from the exponent of the dividend, and the remainder icill be the exponent of the quotient. 2. Divide a6 by a3. ANs. a3. 3. Divide a3... | |
| Elias Loomis - Algebra - 1846 - 380 pages
...following RULE OF EXPONENTS IN DIVISION. In order to divide quantities expressed by different powers of the same letter, subtract the exponent of the divisor from the exponent of the dividend. • EXAMPLES. Divide a8 a7 b6 c* A7 xg y11 By a3 a2 b3 c4 h4 x3 y' Quotient a5 Let it be required to... | |
| Elias Loomis - Algebra - 1846 - 376 pages
...following RULE OF EXPONENTS IN DIVISION. In order to divide quantities expressed by different powers of the same letter, subtract the exponent of the divisor from the exponent of the dividend. EXAMPLES. Divide a8 a* 6e ce A7 xg yii By a3 a3 b3 с4 А4 ж3 у8 Quotient a" Let it be required to... | |
| Thomas Tate (mathematical master.) - 1847 - 138 pages
...to divide a5 by a2. Here we have, g!=axaxaxaxa=qxaxa=a\ In this a? ax a case it will be seen that we subtract the exponent of the divisor from the exponent of the dividend to obtain the exponent of the quotient. Thus, we have generally, -=aŤ-"' ..... (1) a" v ' Let m—n... | |
| Henry Law - Logarithms - 1853 - 84 pages
...divide a power of a given quantity by any other power of the same quantity, it is only necessary to subtract the exponent of the divisor from the exponent of the dividend to obtain the exponent of their quotient. Thus, let it be required to divide sf by x, we have of' -r... | |
| |