| Thomas Keith - Arithmetic - 1822 - 354 pages
...yards, or feet, &c. Prop. 5. Given the area or surface of a circle to find the diameter. Rule.- Divide the area by '7854, and extract the square root of the quotient. Prop. 6. The base and perpendicular of a right angled triangle being given, to find the hypothenuse.... | |
| Oliver Welch - Arithmetic - 1826 - 242 pages
...44X44X07968=154.06688, Ans. PROBLEM VI. The area of a circle given to find the diameter. RULE. — Divide the area by .7854 and extract the square root of the quotient ; the root is the diameter sought. (See application of square roo.t, case 2.) PROBLEM VII. The area given... | |
| William Ruger - Arithmetic - 1832 - 282 pages
...: : 94,248 : Ans. 30 rods. The area of a circle being given, to find the diameter. RULE. — Divide the area by ,7854 and extract the square root of the quotient; the root will be the diameter sought. Or, as 355 : 452 ::so is the area : to the square of the diameter;... | |
| William Ruger - Arithmetic - 1841 - 268 pages
...113 :: 94,248 : Ans. 30 rods. The area of a circle being giten, to -find the diameter. RULE.-^Divide the area by ,7854, and extract the square -root of the quotient ; the root will be the diameter sought. Or, as 355 : 452 : : so is the area : to the square of the diameter... | |
| Arithmetic - 1841 - 200 pages
...44X44X-07953=154-0668S., Ans. PROBLEM VI. The area of a circle given to find the diameter. RULE. — (!). Divide the area by -7854 and extract the square root of the quotient; the root is the diameter sought. (See application of sqtare root, case.2.) PROBLEM VII. The area given... | |
| W. H. CRANK - Arithmetic - 1843 - 340 pages
...length of the arc. Ans. 4-3625 inches. Given the area of a circle to find its diameter. RULE. — Divide the area by '7854, and extract the square root of the quotient, which will give the diameter. Ex. — (1) The area of a circle is 754.7694 feet, what is its diameter?... | |
| Almon Ticknor - Arithmetic - 1846 - 276 pages
...per square foot ? Ays. D615.81. 6.432. The area of a circle given, to find the Sipmeter. RULE. Divide the area by .7854, and extract the square root of the quotient. 1. The area of a circle is 5 acres, 3 rotfds, 26 perches, required the diameter. Thus: 946.000^-.7854=34.7... | |
| Daniel Adams - Arithmetic - 1849 - 142 pages
...in diameter ? Ans. 16. IT 64. The area of a circle being given, to find the diameter. RULE. . Divide the area by '7854, and extract the square root of the quotient. NOTE 1 . This rule being the reverse of the rule 1F63, an analysis is deemed unnecessary. EXAMPLES... | |
| Daniel Adams - Measurement - 1850 - 144 pages
...in diameter ? Ans. 16. ^F G4L* The area of a circle being given, to find the diameter. RULE. Divide the area by '7854, and extract the square root of the quotient. NOTE 1 . This rule being the reverse of the rule ?T63j an analysis is deemed unnecessary. EXAMPLES... | |
| Hugo Reid - Mathematics - 1872 - 148 pages
...times -7854. Problem 18. 372. To find the diameter of a circle, the area being known. Rule. — Divide the area by -7854, and extract the square root of the quotient. Formula — d = 7854 373. Exercises. 1. Find the area of a circle, the diameter of which is 4 yards.... | |
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