 The exponent of any letter in the product is equal to the sum of the exponents of that letter in the factors. This is expressed in general terms, thus: n°x пь = пa+ь.  New First Course in Algebra - Page 91by Herbert Edwin Hawkes, William Arthur Luby, Frank Charles Touton - 1926 - 421 pagesFull view - About this book
 | Charles Davies - Algebra - 1857 - 408 pages
...product of the co-efficients of the multiplicand and multiplier ; and that the exponent of each letter is equal to the sum of the exponents of that letter in both multiplicand and multiplier. And since the same course of reasoning may be applied to any two... | |
 | Charles Davies - Algebra - 1860 - 412 pages
...product of the co-eflioients of the multiplicand and multiplier ; and that the exponent of each letter is equal to the sum of the exponents of that letter in both multiplicand and multiplier. And since the same course of reasoning may be applied to any_ two... | |
 | Elias Loomis - Algebra - 1868 - 386 pages
...acd. 6. 7 Vl8 x 6 V4. Ans. 70 3 /9. 7. 8. 9. V4 x 7 V6 xi V5. Ans. 7 225. We have seen, Art. 58, that the exponent of any letter in a product is equal to the sum of the exponents of this letter in the multiplicand and multiplier. That is, a m xa"=a m +", where m and n are supposed... | |
 | Elias Loomis - Algebra - 1873 - 396 pages
...U^xAv/TF. 8. £v/18x5°v/20. 9. V? x 7 -v/6 x * v/5. Ans. 7 v/l5. 225. We have seen, Art. 58, that the exponent of any letter in a product is equal to the sum of Hve exponents of this letter in the multiplicand and multiplier. That is, a'xa'—a*"^", where m and... | |
 | Edward Olney - Algebra - 1874 - 228 pages
...notation, and to this product affix the letters of both the factors, affecting each with an exponent equal to the sum of the exponents of that letter in the factors. The sign of the product will be + when the signs of the factors are alike, and — when they are unlike.... | |
 | Charles Davies - Algebra - 1875 - 490 pages
...the coeffi cients of the multiplicand and multiplier, and that the expo nent of each letter in the product is equal to the sum of the exponents of that letter in both factors; and since the game course of reasoning may be applied to any two monomials, we have the... | |
 | Edward Olney - Algebra - 1877 - 466 pages
...monomials are multiplied by writing the several letters in connection, and affecting each with an exponent equal to the sum of the exponents of that letter in the factors. EXAMPLES. 1. Separate IZa-bx* into all the possible factors with positive integral exponents. Factors,... | |
 | Edward Olney - Algebra - 1878 - 516 pages
...monomials are multiplied by writing the several letters in connection, and affecting each with an exponent equal to the sum of the exponents of that letter in the factors. EXAMPLES. 1. Separate 12a'kr3 into all the possible factors •with positive integral exponents. Factors,... | |
 | Elias Loomis - Algebra - 1881 - 398 pages
...6. 7VT8x5v/4. Ans. 7. 8. 9. 3/4 x 7 V/6 x * v/S. An». 7 v/IS. 225. We have seen, Art. 58, that $e exponent of any letter in a product is equal to the sum of the exponents of this letter in the multiplicand and multiplier. That is, amxa*=a'*+*, where m and n are supposed to... | |
 | Edward Olney - Algebra - 1881 - 254 pages
...notation, and to this product affix tJw letters of both the factors, affecting each with an exponent equal to the sum of the exponents of that letter in the factors. The sign of the product will be + when the signs of the factors are alike, and — when they are unlike.... | |
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