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" Any exterior angle of a triangle is equal to the sum of the two opposite interior angles. "
A Graded Question Book: Examination Question from the Primaries to the High ... - Page 193
by F. J. Beck - 1899
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A Course of Mathematics ...: Composed for the Use of the Royal Military ...

Charles Hutton - Mathematics - 1811 - 404 pages
...measure of ACE, supposing there to be • known АРБ = p, UPC = p, CP =: d, BC = L, AC = R. Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles (th. 16 Geom.), we have, with respect to the triangle IAP, AIB = p -f- IAP ; and with...
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A Course of Mathematics: For the Use of Academies as Well as ..., Volume 2

Charles Hutton - Mathematics - 1812 - 624 pages
...the measure of ACB, supposing there to be known APB = r, BPC =fi, CP = d, BC = L, AC = R. Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles (th. 1 6 Geom.), we have, •with respect to the triangle IAP, AIB = P+IAP; and with...
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A Treatise on Surveying, Containing the Theory and Practice: To which is ...

John Gummere - Surveying - 1814 - 398 pages
...the angle of elevation BAG = 26° 30'. Required the height of the tree. Calculation. 1. Because the exterior angle of a triangle is equal to the sum of the two interior and opposite ones, the angle BDC = DAC + ACD ; therefore ACD - BDC — DAG = 25° : now in the triangle...
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Elements of Plane and Spherical Trigonometry

Olinthus Gregory - Plane trigonometry - 1816 - 278 pages
...measure of ACB, supposing there to be known c , APB = P, BPC = p, CP = d, BC = -LI AC = B. Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles, we have, with respect- to the triangle IAP, AIB = i> + IAP; and with regard to the...
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A system of practical mathematics; being no.xvi. of a new series of school-books

Scottish school-book assoc - 1845 - 444 pages
...find C, the measure of ACB, supposing there to be known APB=P, BPC= p, CP=d, BC=L, AC=R. Since the exterior angle of a triangle is equal to the sum of the two interior opposite angles, (Geo. prop. ] 9), we have, with respect to the triangle IAP, ZAIB=ZP+UAP ; and with...
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First Lessons in Geometry: Upon the Model of Colburn's First Lessons in ...

Alpheus Crosby - Geometry - 1847 - 190 pages
...aABC + aACB = AmL? M. .-. ACD 4- ACS xa BAG + ABC -j- ACS ? 20. a. ACD *w BAC + ABC ? XXII. A COR. Any exterior angle of a triangle is equal to the sum of the two interior opposite angles. It is of course greater than either singly. Draw CE ]| BA, and prove the same from...
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A complete System of Mensuration ... With many ... Additions ... by J. Trotter

Alexander Ingram - 1851 - 204 pages
...angle ACB. Supposing that APB = P, APC =p; CP = d; AC = C\^ - VP L, and BC = R are known. Since the exterior angle of a triangle is equal to the sum of the two interior and opposite angles ; then the angle AJB = P + IBP, and AIB is also equal to C + CAP ; hence P -f IBP...
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Plane and Solid Geometry: To which is Added Plane and Spherical Trigonometry ...

George Roberts Perkins - Geometry - 1856 - 460 pages
...angle ACB of the triangle ACB. THEOREM vI. The exterior angle, formed ly producing one of the sides of a triangle, is equal to the sum of the two interior and opposite aaigles of the triangle. In the. triangle ABC, if the side AB be produced to D, the exterior...
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Plane and Solid Geometry: To which is Added Plane and Spherical Trigonometry ...

George Roberts Perkins - Geometry - 1860 - 474 pages
...angle ACB of the triangle ACB. THEOREM VI. The exterior angle, formed by producing one of the sides of a triangle, is equal to the sum of the two interior and opposite angles of the triangle. In the triangle ABC, if the side AB be produced to D, the exterior...
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Navigation

James Pryde - Navigation - 1867 - 506 pages
...incidence, their complements are also equal ; hence L BAD = L SAF, and L DBC = L GBA. But since the exterior angle of a triangle is equal to the sum of the two interior angles, L. EBC = L ВАС + L. ACB = L. BAD + L DAG + L ACB = L. BAD + L SAF + L ACB = 2 L BAD + L...
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