 | A. Melrose (Teacher) - Arithmetic - 1795 - 140 pages
...divifor, thus increafed, by the laft. figure placed iu the root : Subtract the produft from the drwdend, and to the remainder annex the next period for a new dividend ; with which proceed in the fame manner, and'fo on,. till all the periods are ufed. I Required the... | |
 | John Davidson, Robert Scott (writing master) - Arithmetic - 1818 - 190 pages
...also on the right of the divisor ; multiply the divisor thus completed ly this nea figure, suUnii.t the product from the dividend, and to the remainder annex the next fart for a new dividend. To the complete divisor add the last figure of the reot, the turn will be... | |
 | Samuel YOUNG (of Manchester.) - 1833 - 272 pages
...both in the root and on the right of the Disisor; also by it multiply the Divisor thus completed, and subtract the Product from the Dividend, and to the...Remainder annex the next period for a new Dividend. To the completed Divisor add the figure last put in the root ; the sum is a new Divisor, with which... | |
 | George Roberts Perkins - Arithmetic - 1841 - 274 pages
...the result will be the TRUE DIVISOR. Multiply the true divisor by this second figure of the root, and subtract the product from the dividend, and to the remainder annex the next period,for a SECCUD DIVIDEND. . ft IV. To the last TRUE DIVISOR, add the Jastfgure of the root, for... | |
 | John Husband (math. master, Berwick.) - 1841 - 126 pages
...together these two lines for the complete divisor; multiply the sum by the second figure in the root ; subtract the product from the dividend, and to the remainder annex the third period for a new dividend. Place the square of the second figure of the root under the complete... | |
 | Arithmetic - 1843 - 142 pages
...product write also the square of the trial-figure, then multiply the sum of these by the trial-figure, subtract the product from the dividend, and to the...remainder annex the next period for a new dividend. EVOLUTION.ciphers for a new divisor, with which find anolner trialfigure, and proceed as before. 1.... | |
 | Pliny Earle Chase - Arithmetic - 1844 - 246 pages
...already found, by the last root figure ; this product added to the divisor, will give the complete divisor. Multiply the complete divisor by the last...root figure, subtract the product from the dividend, annex the next period to the remainder, and proceed as before until the whole root is extracted. If... | |
 | Pliny Earle Chase - 1844 - 258 pages
...already found, by the last root figure ; this product added to the divisor, will give the complete divisor. Multiply the complete divisor by the last...root figure, subtract the product from the dividend, annex the next period to the remainder, and proceed as before until the whole root is extracted. If... | |
 | George Roberts Perkins - Arithmetic - 1846 - 266 pages
...the result will be the TRUE DIVISOR. Multiply the true divisor by this second figurt of the root, and subtract the product from the dividend, and to the remainder annex the next period, for a SECOND DIVIDEND. IV. To the last TRUE DIVISOR, add the last figure of the not, for a new TRIAL DIVISOR,... | |
 | James W. Kavanagh - 1846 - 304 pages
...quotient figure, and enter the product under the dividend ; subtract this product from the dividend above, and to the remainder annex the next period for a new dividend. But should it so happen that the divisor is not contained in the dividend, then enter 0 in the quotient,... | |
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Multiply the true divisor by the last root figure, subtract the product from the dividend, and to the remainder annex the next period for a new dividend. 
