 | Arithmetic - 1818 - 264 pages
...orbit be 596,902,10<} miles how far are we from the Sun ? Ans. 95,000,000miles. PROBLEM VII. To Jind the Area of a circle. RULE. Multiply the square of the diameter by .7854 OR Multiply half the diameter into half the circumference. Ex. I. What is the area of a circle whose... | |
 | Matthew Iley - 1820 - 512 pages
...x50 = 800, area of ACD ; and 10x50 = 500, area of ABD. Sum 1300 square inches, as before. PROBLEM IX. To find the Area of a Circle. RULE. Multiply the square of the diameter by the decimal -7854, and the product will be the area. Let ABCD be a circle, whereof the diameter is... | |
 | Nautical astronomy - 1821 - 708 pages
...429 feet ; this added to the triangle AEB 143 feet, gives the whole area 572 square feet. PROBLEM IV. To find the area of a circle. RULE. Multiply the square of the diameter of the circle by the quantity 0.7854, and yeu will have the sought area. NOTE. Instead of multiplying... | |
 | Nathaniel Bowditch - Nautical astronomy - 1826 - 764 pages
...BODE, 429 feet ; this added to the triangle j gives the whole area 572 square feet. PROBLEM IV. Toßnd the area of a circle. RULE. Multiply the square of the diameter of the circle bj 0.7854, and you will have the sought area. NOTE. Instead of multiplying hy 0.7854... | |
 | Nathaniel Bowditch - Nautical astronomy - 1826 - 732 pages
...this added to the triangle ЛЕВ 143 feet,' gives the whole area Ü72 square feet. PROBLEM IV. Toßnd the area of a circle. RULE. Multiply the square of the diameter of the circle by the quantit v 0.7854, and you will Imve the sought area. NOTE. Instead of multiplying... | |
 | Daniel Parker - Arithmetic - 1828 - 358 pages
...Ans. 2. What is the mean proportional between 15 and 60 ? 60X15=900 ; and ^900=30 JÎn». PROB. V. — To find the area of a circle, Rule. — Multiply the square of the diameter by ,7854, and the product will be the area. Or, multiply the square of the circumference by ,07958, and the product... | |
 | Calvin Tracy - Arithmetic - 1842 - 306 pages
...Ans. 2. What is the diameter of a wheel whose circumference is 50 feet ? Ans. 15.9 +feet. PROB. 14. To find the area of a circle. RULE. — Multiply the square of the DIAMETER by the decimal .7854, or by the fraction -f^-; or, multiply the square of the CIRCUMFERENCE by the decimal... | |
 | William Vogdes - Arithmetic - 1847 - 324 pages
...is its diameter ? 3. What is the diameter of a circle whose circumference is 128 feet? PROBLEM XIX. To find the area of a circle. RULE. Multiply the square of the diameter by .7854, and the product will be the area. Or multiply the square of the circumference by .07958, and the product... | |
 | Ezra S. Winslow - Business mathematics - 1853 - 264 pages
...is the diameter of a circle that contains an area of 784 square feet? ' * MENSURATION OF SUPERFICES. To find the area of a circle. RULE. — Multiply the square of the diameter by .7854, (.785398) ; or, multiply the square of the circumference by .07958 ; or, multiply half the circumference... | |
 | Silas Lawrence Loomis - Arithmetic - 1859 - 324 pages
...CXIV. — To FIND THE DIAMETER OF A CIRCLE. RULE. — Divide the circumference by n. PROB. CXV. — To FIND THE AREA OF A CIRCLE. RULE. — Multiply the square of the diameter by £ *; or \ the product of the circumference and diameter; or the product of half the diameter, by half... | |
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To find the area of a circle. Rule — Multiply the square of the diameter by .7854; or the square of the radius by 3.1416; or the square of the circumference by .07958. Find the area of a piston 20 in. in diam. Answer— 20! 
