## Exercises in Wentworth's Geometry: With Solutions |

### Other editions - View all

Exercises in Wentworth's Geometry: With Solutions (1896) George Albert Wentworth No preview available - 2008 |

Exercises in Wentworth's Geometry: With Solutions (Classic Reprint) George Albert Wentworth No preview available - 2017 |

Exercises in Wentworth's Geometry: With Solutions (Classic Reprint) George Albert Wentworth No preview available - 2017 |

### Common terms and phrases

ABē altitude ANALYSIS angle base bisect bisector centre chord circumference circumscribed common cone constructed spheres cylinder diagonals diameter distance divide drawn edges equally distant equiangular polygon equidistant equilateral triangle Find the area find the lengths Find the locus frustum given plane given point given radius Hence hypotenuse inches inscribed intersection isosceles trapezoid isosceles triangle Join AC latus rectum Let ABCD line joining measured by arc meet middle point MN and PQ parallel parallelogram pass a plane perimeter perpendicular Phillips Exeter Academy plane MN polygon produced PROOF prove pyramid quadrilateral radii rectangle respectively rhombus right circular right triangle S-ABC segment side similar slant height SOLUTION spherical square feet surface tangent tetrahedron trihedral vertex volume

### Popular passages

Page 22 - ... is less than the sum but greater than the difference of the radii ; (4) is equal to the difference of the radii ; (5) is less than the difference of the radii.

Page 20 - The sum of the perpendiculars dropped from any point in the base of an isosceles triangle to the legs, is equal to the altitude upon one of the arms.

Page 144 - The line that joins the feet of the perpendiculars dropped from the extremities of the base of an isosceles triangle to the opposite sides is parallel to the base.

Page 20 - The sum of the perpendiculars from any point within an equilateral triangle to the three sides is equal to the altitude of the triangle (Fig.

Page 40 - Prove that the locus of the vertex of a triangle, having a given base and a given angle at the vertex, is the arc which forms with the base a segment capable of containing the given angle (§ 318).

Page 137 - Find the angle subtended at the centre of a circle by an arc whose length is equal to the radius of the circle.

Page 6 - If the diagonals of a quadrilateral bisect each other, the figure is a parallelogram.

Page 96 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. A D A' Hyp. In triangles ABC and A'B'C', To prove AABC A A'B'C' A'B' x A'C ' Proof. Draw the altitudes BD and B'D'.

Page 75 - ... by four times the square of the line joining the middle points of the diagonals.

Page 5 - ABC and ABD are two triangles on the same base AB, and on the same side of it, the vertex of each triangle being without the other. If AC equals AD, show that BC cannot equal BD (§ 154).