A Course of Mathematics: Composed for the Use of the Royal Military Academy |
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Page 359
... Radius of a circle is a line drawn from the centre to the circumference . 47. The Diameter of a circle is a line drawn through the centre , and terminating at the circumference on both sides . 48. An Arc of a circle is any part of the ...
... Radius of a circle is a line drawn from the centre to the circumference . 47. The Diameter of a circle is a line drawn through the centre , and terminating at the circumference on both sides . 48. An Arc of a circle is any part of the ...
Page 380
... radius FB . From each of these take away the common part FG , and the remainder GA will be greater than the remainder GB . But the point G being supposed the centre of the inner circle , its two radii , GA , GD , are equal to each other ...
... radius FB . From each of these take away the common part FG , and the remainder GA will be greater than the remainder GB . But the point G being supposed the centre of the inner circle , its two radii , GA , GD , are equal to each other ...
Page 381
... radius , is a tangent to the circle . Let the line ADB be perpendicular to the radius CD of a circle ; then shall AB touch the circle in the point D only . From any other point E in the line AB draw CFE to the centre , cutting the ...
... radius , is a tangent to the circle . Let the line ADB be perpendicular to the radius CD of a circle ; then shall AB touch the circle in the point D only . From any other point E in the line AB draw CFE to the centre , cutting the ...
Page 382
... radius CD be perpendicular to the tangent AB . [ See the last figure . ] For , the line AB being wholly without the ... radius EC to the point of contact , and the radius EF perpendicular to the chord at H. Then the radius EF , being ...
... radius CD be perpendicular to the tangent AB . [ See the last figure . ] For , the line AB being wholly without the ... radius EC to the point of contact , and the radius EF perpendicular to the chord at H. Then the radius EF , being ...
Page 386
... radius DH , and draw HI perpendicular to CD . Then , since DEH is a triangle , and the perp . HI bisects the chord CD ( th . 41 ) , the line CE is equal to the difference of the segments DI , EI , the sum of them being DE . Also ...
... radius DH , and draw HI perpendicular to CD . Then , since DEH is a triangle , and the perp . HI bisects the chord CD ( th . 41 ) , the line CE is equal to the difference of the segments DI , EI , the sum of them being DE . Also ...
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Common terms and phrases
algebraic axis bisected called centre circle circumference coefficient contained Corol cosec cosine cube root curve decimal denominator denote diameter difference differential co-efficient distance Divide dividend division divisor draw dy dx equal EXAMPLES exponent expression extract factors feet figure fraction given number greater greatest common measure Hence hyperbola inches latus rectum least common multiple logarithm manner monomial multiply negative nth root number of terms parallel parallelogram perpendicular plane polynomial positive Prob problem Prop proportional proposed equation quotient radius ratio rectangle Reduce remainder right angles rule sides sine square root straight line Substituting subtract tangent Taylor's theorem THEOREM unknown quantity VULGAR FRACTIONS whole number yards