A Course of Mathematics: Composed for the Use of the Royal Military Academy |
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Page 7
... given number 4658 4 X 999 + 4 + 6 × 99 + 6 + 5 × 9 + 5 + 8 = 4 × 999 + 6 × 99+ 5 × 9 + 4 + 6 + 5 + 8 ; and 4658 ÷ 9 = ( 4 × 999 + 6 × 99 + 5 × 9 + 4 + 6 + 5 + 8 ) ÷ 9. But 4 × 999 +6 × 99 +5 × 9 is evidently divisible by 9 , without a ...
... given number 4658 4 X 999 + 4 + 6 × 99 + 6 + 5 × 9 + 5 + 8 = 4 × 999 + 6 × 99+ 5 × 9 + 4 + 6 + 5 + 8 ; and 4658 ÷ 9 = ( 4 × 999 + 6 × 99 + 5 × 9 + 4 + 6 + 5 + 8 ) ÷ 9. But 4 × 999 +6 × 99 +5 × 9 is evidently divisible by 9 , without a ...
Page 44
... given fractions have a common mea- sure , let them be divided by it ; then multiply the terms of each given fraction by the quotient arising from the other's denominator . 2. When the less denominator of two fractions exactly divides ...
... given fractions have a common mea- sure , let them be divided by it ; then multiply the terms of each given fraction by the quotient arising from the other's denominator . 2. When the less denominator of two fractions exactly divides ...
Page 59
... given number into periods of two figures each , by setting a point over the place of units , another over the place of hundreds , and so on , over every second figure , both to the left hand in integers , and to the right in decimals ...
... given number into periods of two figures each , by setting a point over the place of units , another over the place of hundreds , and so on , over every second figure , both to the left hand in integers , and to the right in decimals ...
Page 64
... given power or number , n the index of the power , A the assumed power , r its root , R the required root of N. Then , as the sum of n + 1 times A and n 1 times N , is to the sum of n + 1 times N and n 1 times A , so is the assumed root ...
... given power or number , n the index of the power , A the assumed power , r its root , R the required root of N. Then , as the sum of n + 1 times A and n 1 times N , is to the sum of n + 1 times N and n 1 times A , so is the assumed root ...
Page 67
... Given the extremes , and the number of terms ; to find the common difference . RULE . - Subtract the less extreme from the greater , and divide the remainder by 1 less than the number of terms , for the common difference . EXAMPLES . 1 ...
... Given the extremes , and the number of terms ; to find the common difference . RULE . - Subtract the less extreme from the greater , and divide the remainder by 1 less than the number of terms , for the common difference . EXAMPLES . 1 ...
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Common terms and phrases
algebraic axis bisected called centre circle circumference coefficient contained Corol cosec cosine cube root curve decimal denominator denote diameter difference differential co-efficient distance Divide dividend division divisor draw dy dx equal EXAMPLES exponent expression extract factors feet figure fraction given number greater greatest common measure Hence hyperbola inches latus rectum least common multiple logarithm manner monomial multiply negative nth root number of terms parallel parallelogram perpendicular plane polynomial positive Prob problem Prop proportional proposed equation quotient radius ratio rectangle Reduce remainder right angles rule sides sine square root straight line Substituting subtract tangent Taylor's theorem THEOREM unknown quantity VULGAR FRACTIONS whole number yards