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== {log. (2cx + b + 2 √c√a + bx + cx2) — log. 2c}

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ON EXPONENTIAL FUNCTIONS.

1o. If X = ƒ (a), then the function Xdæ, if we make a2 = u wiù become f(u) du

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dx

2o. Differentiating Xex, we have e da (X+) so that every exponential function in which the factor of e* dx is composed of two parts, one of which is the first differential co-efficient of the other, will be easily integrated. For example

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In like manner, if we make 1+x=z, we shall find

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In every other case, however, we must have recourse to the method of integration by paris.

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u =

=

a dx. 2" and considering an in he first instance

=fa2

ax xn
log, a

as constant.

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Treating a 2-1 dx, &c. in the same manner, we shall finally have

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It is manifest that the same method is applicable to Xɑ dx, where X is any entire algebraical function of x.

But if the exponent n be negative, it is manifest that the exponent of a must go on increasing; and therefore, in the integration by parts we must consider a as constant in the first instance, in this manner, if

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We cannot, however, proceed with our calculation beyond this point, because we should obtain a result = α

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We can, however, approximate to it in the following manner

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If n is fractional, one or other of the above methods will enable us to reduce the exponent of x until its value lies between 0 and 1, or . 1, and we shall then be enabled to approximate to the required integral by series.

On Logarithmic Functions.

Let it be required to integrate

Xda log" a

where X is any algebraic function of x.

If n is a positive whole number we may integrate by the method of parts, regarding log." x as constant in the first instance. We shall then have

da

dx

ƒX da log." x = log." x ƒX dæ - nf (log."-fx dx). and since fx dx is supposed to be known by the principles already establish

ed, we perceive that the integration of the proposed function is reduced to that of one whose form is the same, and in which the exponent of the logarithm is reduced by unity. The same process is applicable to this new function, and thus the integration will be completed step by step.

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But if n be integral and negative, we perceive that, as in the case of exponential functions, in performing the integration by parts of ƒ X log." x dx, we must in the first instance suppose X constant.

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