 | Adrien Marie Legendre - Geometry - 1819 - 574 pages
...construction, AG = DE ; therefore AH = DF. The two triangles AGH, DEF, have the two sides and the included angle of the one respectively equal to two sides and the included angle of the other ; they are consequently equal. But the triangle AGH is similar to ABC; therefore DEF is... | |
 | Adrien Marie Legendre, John Farrar - Geometry - 1825 - 280 pages
...ABD, in the same manner as two plane triangles are applied, when they have two sides and the included angle of the one respectively equal to two sides and the included angle of the other (36). Therefore all the parts of the triangle EFG will be equal to those of the triangle... | |
 | Adrien Marie Legendre - Geometry - 1825 - 276 pages
...BF = BC, for the same reason ; consequently the triangles ABF, HBC, have two sides and the included angle of the one respectively equal to two sides and the included angle of the other ; they are therefore equal (36). The triangle ABF is half of the rectangle BE], which... | |
 | Adrien Marie Legendre - Geometry - 1841 - 288 pages
...BF= BC, for the same reason ; consequently the triangles ABF, HBC, have two sides and the included angle of the one respectively equal to two sides and the included angle of the other ; they are therefore equal (36). The triangle ABF is half of the rectangle BE,* which... | |
 | Charles Davies - Geometry - 1850 - 218 pages
...moreover, the side BD is common ; hence the two triangles have two sides and the included angle of the one, equal to two sides and the included angle of the other : the triangles are therefore equal, and consequently, AD is equal to BC, and the angle ADB to the angle... | |
 | Charles Davies - Geometry - 1850 - 238 pages
...moreover, the side BD is common ; hence the two triangles have two sides and the included angle of the one, equal to two sides and the included angle of the other : the triangles are therefore equal, and consequently, AD is equal to BC, and the angle ADB to the angle... | |
 | Charles Davies - Geometry - 1886 - 340 pages
...moreover, the side BD is common | hence the two triangles have two sides and the included an^.u of the one, equal to two sides and the included angle of the Other : the triangles are therefore equal, and consequently AD is equal to BC, and the angle ADB to the angle DBC... | |
 | Eli Todd Tappan - Geometry, Modern - 1864 - 288 pages
...INCLUDED ANGLE. 284. Theorem. — Two triangles are equal when they have two sides and the included angle of the one, respectively equal to two sides and the included angle of the other. If the angle A is equal to D, and the side AB to angle, if necessary, so that both shall... | |
 | 1872 - 398 pages
...lisccls the base, the triangle is isosceles. 1. When two triangles have two sides and included angle of one respectively equal to two sides and the included angle of the other, the triangles are equal in all respects. II. When two angles of a triangle are equal the opposite sides... | |
 | Eli Todd Tappan - Geometry - 1868 - 444 pages
...INCLUDED ANGLE. 2S4. Theorem — Two triangles are equal when ihey have two sides and the included angle of the one, respectively equal to two sides and the included angle of the other. If the angle A is equal to D, and the side AB to the side DF, and AC to DE, then the... | |
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If two triangles have two sides and the inchtded angle of the one respectively equal to two sides and the included angle of the other, the two triangles are equal in all respects. 
