EXERCISE 63. REVIEW. When a = 2, b = - 2, and c = 4; find the value of : 1. √a3+b3 + c3 - (a - b - c). 3. (b - 5) (b - 4) – 3 (b - 2) (b − 1) + 3 (b + 1) (6 + 2). 3 x3 + 10 x2 + 7x-2 4. Reduce to lowest terms 3x2 + 13x2 + 17 x + 6 5. Simplify: 1 x-3 (x - 3) (x - 2) (x - 1)(x - 3) (x - 1) (x - 2) - - 1)(x-3) + (x-1)(x-2) HINT. Add the first two fractions; then their sum and the third fraction and this result to the fourth fraction. 12. X x2 + 6 xy + 5 y2 ^^ x2 + 4x +4x+2 z2 + xy 13. x2 + yz + zx + zh + (x - y) (x - 2) (y - z) (y - x) (z - x) (z - y) 14. (1+1)+(1-1). x+2y y -x x2+x-2 8 x x2-4 18.(+++)+(+24) x+y 2 19.(1-1)(1+2+1-243). (x + 1) (x + 2) 1+2x2 24.(1-1+1)(1). 26.++_+c-a_c+a-b_a+b-c. Multiply by 33, the L. C. M. of the denominators. Then, 11x-3x + 3 = 33x - 297, 11x-3x-33 x = 297 3, - 25 x = 300. .. x = 12. NOTE. Since the minus sign precedes the second fraction, in removing the denominator the sign of every term of the numerator is changed. 8 2. Solve 2+1-2-1-4-1 The L. C. D. = (2x + 1) (2x – 1). Multiply by the L. C. D., and we have, Reducing, 4x2 + 4x + 1 - (4x2 - 4x + 1) = 8. .. 4 x2 + 4x + 1-4x2+4x-1= 8. x = 1. 174. To Clear an Equation of Fractions, therefore, Multiply each term by the L. C. M. of the denominators. If a fraction is preceded by a minus sign, the sign of every term of the numerator must be changed when the denominator is removed. |