Elements of Geometry and Trigonometry |
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Page 122
... area CA = × CA2 : hence the area of a circle is equal to the product of the ... areas of circles are to each other as the squares of their radii , which agrees ... find the cir- cumference when the radius is given ; and for effecting this ...
... area CA = × CA2 : hence the area of a circle is equal to the product of the ... areas of circles are to each other as the squares of their radii , which agrees ... find the cir- cumference when the radius is given ; and for effecting this ...
Page 124
... find the approximate ratio of the circumference to the diameter . Let the ... find the inscribed octagon A'✓8-2.8284271 , and the circumscribed octagon B ' = ; = 3.3137085 . The inscribed and the ... area of the circle 124 GEOMETRY .
... find the approximate ratio of the circumference to the diameter . Let the ... find the inscribed octagon A'✓8-2.8284271 , and the circumscribed octagon B ' = ; = 3.3137085 . The inscribed and the ... area of the circle 124 GEOMETRY .
Page 210
... area of a triangle is equal to half its base into the altitude , ( Bk . IV ... find the sides . PROBLEM VII . In a right angled triangle , having given the ... area of a rectangle 210 APPLICATION OF ALGEBRA.
... area of a triangle is equal to half its base into the altitude , ( Bk . IV ... find the sides . PROBLEM VII . In a right angled triangle , having given the ... area of a rectangle 210 APPLICATION OF ALGEBRA.
Page 211
Adrien Marie Legendre. PROBLEM VIII . Having given the area ... find the sides of the triangle . PROBLEM XI . In a triangle , having given the two sides about the vertical angle , together with the line bisecting that angle and terminating in ...
Adrien Marie Legendre. PROBLEM VIII . Having given the area ... find the sides of the triangle . PROBLEM XI . In a triangle , having given the two sides about the vertical angle , together with the line bisecting that angle and terminating in ...
Page 273
... 15 ′ 13 ′′ , and c = ' = 76 ° 35 ′ 36 ′′ ; to find the remain- ing parts . Ans . a = -40 ° 0 ' 10 " b = 50 ° 10 ′ 30 ′′ C = 58 ° 23 ′ 41 ′′ . S 274 MENSURATION OF SURFACES . The area , or content SPHERICAL TRIGONOMETRY . 273.
... 15 ′ 13 ′′ , and c = ' = 76 ° 35 ′ 36 ′′ ; to find the remain- ing parts . Ans . a = -40 ° 0 ' 10 " b = 50 ° 10 ′ 30 ′′ C = 58 ° 23 ′ 41 ′′ . S 274 MENSURATION OF SURFACES . The area , or content SPHERICAL TRIGONOMETRY . 273.
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Common terms and phrases
adjacent adjacent angles altitude angle ACB angle BAC ar.-comp base multiplied bisect Book VII centre chord circ circumference circumscribed common cone convex surface Cosine cylinder diagonal diameter dicular distance divided draw drawn equally distant equations equivalent feet figure find the area formed four right angles frustum given angle given line gles greater homologous sides hypothenuse inscribed circle inscribed polygon intersection less Let ABC logarithm number of sides opposite parallelogram parallelopipedon pendicular perimeter perpen perpendicular perpendicular let fall plane MN polyedron polygon ABCDE PROBLEM proportional PROPOSITION pyramid quadrant quadrilateral quantities radii radius ratio rectangle regular polygon right angled triangle S-ABCDE Scholium secant segment similar Sine Cotang slant height solid angle solid described sphere spherical polygon spherical triangle square described straight line tang tangent THEOREM triangle ABC triangular prism vertex