 | Charles Vyse - Arithmetic - 1785 - 350 pages
...Multiply Half the the Circumference by Half the Diameter, and the Product will be the Area. Or, 2. Multiply the Square of the Diameter by ,78,54, and' the Product will be the Area. Or, • 3. Multiply the Square of the Circumference by ,079574, and the Product will be the Area. Or,... | |
 | Charles Hutton - Measurement - 1788 - 728 pages
...the area CAE of the whole circle or feftor accordingly. ^_. £. D. * RULE II. « Multiply the fquare of the diameter by '7854, and the product will be the area* EXAMPLES. i, What is the area of a circle whofe diameter is I, and circumference 3'i4i6? Vl4-l6 XI 0 . / i—... | |
 | Charles Vyse - Arithmetic - 1806 - 342 pages
...1. Multiply Half the Circumference by Half the Diameter, and tin- Product will 1& the Area. Or, 2. Multiply the Square of the Diameter by ,7854, and the Product will be the Area. Or, 3. Multiply the Square of the Circumference by ,079574, and the Product will be the Area. Or, 4.... | |
 | Oliver Welch - Arithmetic - 1812 - 236 pages
...and circumference 44 rods ? > r<fe. rils. - f, 14-ff X 44 -f- 1 = 1 54 square rods, .fn*, PROBLEM IV. The diameter given to find the area. RULE. Multiply the square of the diameter by 07854 the product is the area. Example. 1. What is the area of a circle whose diameter is rds. 14 rods?... | |
 | Oliver Welch - Arithmetic - 1857 - 244 pages
...rods, Ans. The same question done by rule second. Ux44=616^-J=154 sq. rds. Ans. '..• PROBLEM IV. I The diameter given to find the area. RULE,— Multiply the square of the diameter by •5r854 the product is the area. Example. 1. What is the area of a circle whose diameter is 14 rods... | |
 | Nathan Daboll - Arithmetic - 1815 - 250 pages
...circumference^ and the product is the area ; or if the diameter is given without the circumference, multiply the square of the diameter by ,7854 and the product will be the area. EXAMPLE8. 1. Required the area of a circle whose diameter 'is 12 inches, and circumference 37,7 inches.... | |
 | Nathan Daboll - Arithmetic - 1817 - 252 pages
...circumference, and the product is the area; or if the diameter is given without the circumference, multiply the square of the diameter by ,7854 and the product will be the area. EXAMPLES. 1. Required the area of a circle whose diameter is 12 inches, and circumference 37,7 inches. v- 18,85=half... | |
 | Thomas Keith - 1817 - 306 pages
...the area of a circle whose diameter is d. circumference and diameter, 'and it will give the area. 2. Multiply the square of the diameter by 7854, and the product will be the area. 3. As 452 is to 355, so is the square of the diamuter to the area. 3' "3 : 355 :: diameter I : circumference... | |
 | Nathan Daboll - Arithmetic - 1818 - 246 pages
...circumference, and the product is the area ; or if the diameter is given • •without the circumference, multiply the square of the diameter by ,7854 and the product will be- the area. EXAMPLES. 1. Required the area of a circle whose diameter is 12 inches, and circumference 37,7 inches. 18,85=half... | |
 | Nathan Daboll - Arithmetic - 1820 - 256 pages
...product is the area ; or if the -diameter is j»iven without the circumference, multiply the square oi the diameter by ,7854 and the product will be the area. EXAMPLES. 1. Required thearfch of a circle whose diameter is 12 inches, and circumference 37,7 inches. 1 8.85 =half... | |
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... multiply the square of the diameter by ,7854 and the product will be- the area. 
