 | George Fisher (accountant.) - 1811 - 302 pages
...or Breadth of the 16 Ditch. lof 3. If tj!e Height of a Tower or Perpendicular B were required, then the Square Root of the Difference of the Squares of the Hypotenuse and Base is the height of tb« jferpendieular BC, thus: 2500 900 (30 Yards. Number of Mtn being given to... | |
 | Michael Walsh - Arithmetic - 1828 - 312 pages
...perpendicular is the length of the base. 13 The base and hypotenuse given, to find the perpendicular, RULE. The square root of the difference of the squares of the hypotenuse and base is the height of the perpendicular. NB The two last questions may be varied for examples to the... | |
 | Michael Walsh - Arithmetic - 1828 - 318 pages
...perpendicular и the length Of the base. The base and hypotenuse given, to find the perpendicular. Rcr.E. Tlie square root of the difference of the squares of the hypotenuse and base is the height of the perpendicular. NB The two last questions may be varied for examples to tlio... | |
 | Arithmetic - 1829 - 196 pages
...ROOT of the suit OF TUB SQUARES of the two shortest sides, is the length of the HYPOTENUSE. RULE 2. The SQUARE ROOT of the DIFFERENCE OF THE SQUARES of the HYPOTENUSE and EITHER of the other sides, is the length of the REMAINING side. Applying the rule to example 18, \/4a... | |
 | Tobias Ostrander - Measurement - 1833 - 172 pages
...the hypotenuse and either leg of a right-angled triangle are given, to find the other. Rule—Extract the Square root of the difference of the squares of...right-angled triangle is 25 chains, and the base 20 chains—What is the length of the perpendicular. Ans. 15 chains. 2. The hypotenuse of a right-angled... | |
 | Samuel YOUNG (of Manchester.) - 1833 - 272 pages
...is equal to the square root of the sum of the squares of the two sides, and either side is equal to the square root of the difference of the squares of the hypotenuse and other side. (1) Three sides of a triangle are 3, 4, and 5, taking any two of them as given, required... | |
 | Francis Walkingame - 1833 - 204 pages
...the length of the base. Case 3. The base and hypotenuse being given, to find the perpendicular. RULE. The square root of the difference of the squares of the hypotenuse and base is the height of the perpendicular. (26) The top of a castle from the ground is 45 yards high,... | |
 | George Alfred - Arithmetic - 1834 - 336 pages
...60x60=3600 45x45=2025 y5625=75 Answer. PROBLEM 7. Given the base and hypothenuse, to find the perpendicular. RULE. Extract the square root of the difference of the squares of the base and hypothenuse, and that will be the height of the perpendicular required. AN EXAMPLE. When the... | |
 | Frederick Emerson - Arithmetic - 1834 - 300 pages
...difference of the squares of the hypotenuse and base is equal to the perpendicular. PROPOSITION 4U,. The square root of the difference of the squares of the hypotenuse and perpendicular is equal to the base. By observing the above propositions, when any two sides of a right-angled... | |
 | Education - 1835 - 496 pages
...or height of the wall. Ans. 24 feet The hypothenuse and perpendicular being given to find the base. RULE. — Extract the square root of the difference of the squares of the liypothenuse and perpendicular, and the said root will be the width of the base. 47. Admitting the... | |
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... is equal to the square root of the difference of the squares of the hypotenuse and the other leg. 
