 | Mathematics - 1801 - 650 pages
...30 • Or 6 : i :: 28,2744 : 4-7124 Or 3 : 30 :: -05236X9 : 4'7^4 36 4-7124 the answer. RULE a.* . From 8 times the chord of half the arc subtract the chord of the whole arc, and ~ of the remainder "-'ill be the length of the arc nearly. 2. The * DEMONSTRATION. Let the radius OD~r, and sine DB ,.... | |
 | Samuel Webber - Mathematics - 1808 - 466 pages
...3'1416 9 As 180 : 30 Or 6 : 1 : : 282744 ; 4'7124 Or a : 30 : : '05236x9 : 4'7124 36 4'? 124 the answer. RULE*. From 8 times the chord of half the arc subtract...the whole arc, and | of the remainder will be. the kpgth, of the arc nearly. * DEM0NSTRATI0N. Let the radius CA=r, and sine AP лл. Then will the chord... | |
 | Anthony Nesbit, W. Little - Measurement - 1822 - 916 pages
...French iaticians, to 128. PROBLEM XII. To Jtnd the length of the arc of a circle. RULE I. By the Pen. 8 times the chord of half the arc subtract the chord of the whole ate, and i of the remainder will be the length of the arc, nearly. Note 1. Half the chord of the whole... | |
 | Anthony Nesbit - Surveying - 1824 - 474 pages
...Bonnycastle's As* 'ronomy, page 277. PROBLEM XIV. To find the length of any arc of a circle. RULE I. From 8 times the chord of half the arc subtract the...remainder . will be the length of the arc, nearly. Kote. Half the chord of the whole arc, the chord of half the arc, and the versed sine are sides of... | |
 | John Nicholson - Great Britain - 1825 - 838 pages
...180 : 30 Or 6 : 1 : : 282744 : 47124 Or 3 : 30 : : '05236 X 9 : 47124 90 47124 the answer. Rule 2. From 8 times the chord of half the arc subtract the...remainder will be the length of the arc nearly. Ex. 2. The chord AB (Prob. 8.) of the whole arc being 4'65874, and the chord AD of the half arc 2'34947... | |
 | John Nicholson - Machinery - 1825 - 822 pages
...180 : 30 Or 6 : 1 : : 282744 : 47124 Or 3 : 39 : : '05236 x 9 : 47124 90 47124 the answer. Rule 2. From 8 times the chord of half the arc subtract the...arc, and ' of the remainder will be the length of viie arc nearly. Ex. 2. The chord AB (Proli. 8.) of the whole arc being 4-65874, and the chord AD of... | |
 | John Nicholson (civil engineer.) - Great Britain - 1825 - 1008 pages
...: 30 Or 6 : 1 : : 282744 : 47124 Or 3 : 30 : : '05236 X 9 : 4-7124 90 4*7124 the answer. R'i!,- 2. From 8 times the chord of half the arc subtract the chord of tbe whole arc, and ' of the remainder will be the length of the arc nearly. Ex. 2. The chord AB (Prol.... | |
 | William Galbraith - Astronomy - 1827 - 430 pages
...radius of the circle multiplied by 0.0174533 and by the number of degrees in the arc. Or, from eight times the chord of half the arc subtract the chord of the whole arc, one third of this remainder is the length of the arc nearly. 9. Circular Sector. — The area is equivalent... | |
 | John Nicholson (Civil engineer) - Building - 1830 - 240 pages
...As 180 : 30 Or 6 : 1 : : 282744 : 47124 Or 3: 30 : : 105236 x 9:47124 90 47124 the answer. Rule 2. From 8 times the chord of half the arc subtract the chord of the whole arc, and .1 of the remainder will be the length of the arc nearly. Ex. 2. The chord AB (Prob. 8.) of the whole... | |
 | John Nicholson (Esq. Civil Engineer.) - Great Britain - 1831 - 432 pages
...180 : 30 Or6 : 1 : : 282744:4.7124 Or 3 : 30 : : .05236 X 9 : 4.7124 90 4.7124 the answer. Rule 2. From 8 times the chord of half the arc subtract the chord of the whole arc, and I of the remainder will be the length of the arc nearly. Ex. 2. The chord AB, (Prob. 8,) of the whole... | |
| |
From 8 times the chord of half the arc subtract the chord of the whole arc, and ' of the remainder will be the length of the arc nearly. 
