| Mathematics - 1801 - 658 pages
...30 • Or 6 : i :: 28,2744 : 4-7124 Or 3 : 30 :: -05236X9 : 4'7^4 36 4-7124 the answer. RULE a.* . **From 8 times the chord of half the arc subtract the chord of the whole arc, and ~ of the remainder** "-'ill be the length of the arc nearly. 2. The * DEMONSTRATION. Let the radius OD~r, and sine DB ,.... | |
| Samuel Webber - Mathematics - 1808 - 466 pages
...3'1416 9 As 180 : 30 Or 6 : 1 : : 282744 ; 4'7124 Or a : 30 : : '05236x9 : 4'7124 36 4'? 124 the answer. **RULE*. From 8 times the chord of half the arc subtract...the whole arc, and | of the remainder will be. the** kpgth, of the arc nearly. * DEM0NSTRATI0N. Let the radius CA=r, and sine AP лл. Then will the chord... | |
| Anthony Nesbit, W. Little - Measurement - 1822 - 916 pages
...French iaticians, to 128. PROBLEM XII. To Jtnd the length of the arc of a circle. RULE I. By the Pen. **8 times the chord of half the arc subtract the chord of the whole** ate, and i of the remainder will be the length of the arc, nearly. Note 1. Half the chord of the whole... | |
| Anthony Nesbit - Surveying - 1824 - 476 pages
...Bonnycastle's As* 'ronomy, page 277. PROBLEM XIV. To find the length of any arc of a circle. RULE I. **From 8 times the chord of half the arc subtract the...remainder . will be the length of the arc, nearly.** Kote. Half the chord of the whole arc, the chord of half the arc, and the versed sine are sides of... | |
| John Nicholson - Machinery - 1825 - 838 pages
...180 : 30 Or 6 : 1 : : 282744 : 47124 Or 3 : 30 : : '05236 X 9 : 47124 90 47124 the answer. Rule 2. **From 8 times the chord of half the arc subtract the...remainder will be the length of the arc nearly. Ex.** 2. The chord AB (Prob. 8.) of the whole arc being 4'65874, and the chord AD of the half arc 2'34947... | |
| John Nicholson - Machinery - 1825 - 822 pages
...180 : 30 Or 6 : 1 : : 282744 : 47124 Or 3 : 39 : : '05236 x 9 : 47124 90 47124 the answer. Rule 2. **From 8 times the chord of half the arc subtract the...arc, and ' of the remainder will be the length of** viie arc nearly. Ex. 2. The chord AB (Proli. 8.) of the whole arc being 4-65874, and the chord AD of... | |
| John Nicholson (civil engineer.) - Great Britain - 1825 - 1008 pages
...: 30 Or 6 : 1 : : 282744 : 47124 Or 3 : 30 : : '05236 X 9 : 4-7124 90 4*7124 the answer. R'i!,- 2. **From 8 times the chord of half the arc subtract the chord of** tbe whole arc, and ' of the remainder will be the length of the arc nearly. Ex. 2. The chord AB (Prol.... | |
| William Galbraith - Astronomy - 1827 - 412 pages
...radius of the circle multiplied by 0.0174533 and by the number of degrees in the arc. Or, from eight **times the chord of half the arc subtract the chord of the whole arc,** one third of this remainder is the length of the arc nearly. 9. Circular Sector. — The area is equivalent... | |
| John Nicholson (Civil engineer) - Building - 1830 - 238 pages
...As 180 : 30 Or 6 : 1 : : 282744 : 47124 Or 3: 30 : : 105236 x 9:47124 90 47124 the answer. Rule 2. **From 8 times the chord of half the arc subtract the chord of the whole arc, and** .1 of the remainder will be the length of the arc nearly. Ex. 2. The chord AB (Prob. 8.) of the whole... | |
| John Nicholson (Esq. Civil Engineer.) - Great Britain - 1831 - 432 pages
...180 : 30 Or6 : 1 : : 282744:4.7124 Or 3 : 30 : : .05236 X 9 : 4.7124 90 4.7124 the answer. Rule 2. **From 8 times the chord of half the arc subtract the chord of the whole arc, and** I of the remainder will be the length of the arc nearly. Ex. 2. The chord AB, (Prob. 8,) of the whole... | |
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