A Practical System of Mensuration of Superficies and Solids ... |
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Page 21
... obtained by finding parallelograms which are equal to them . C 9 C B If the parallelogram be divided into D small ... obtain the number of small parallelograms , ce , contained in the large parallelogram , ABCD , we have only to multiply ...
... obtained by finding parallelograms which are equal to them . C 9 C B If the parallelogram be divided into D small ... obtain the number of small parallelograms , ce , contained in the large parallelogram , ABCD , we have only to multiply ...
Page 23
... obtain , then , the number of squares in the large parallelɔ- A C C B gram , we have only to multiply the number of squares in one of the small parallelograms ( ABcd , ) by the number of such parallelograms contained in the whole figure ...
... obtain , then , the number of squares in the large parallelɔ- A C C B gram , we have only to multiply the number of squares in one of the small parallelograms ( ABcd , ) by the number of such parallelograms contained in the whole figure ...
Page 25
... obtained by multiplying the length into the breadth . Now , if the area and one side of any parallelo- gram be given , the other side may be found by dividing the area by the given side . So , also , if the area of a square be given ...
... obtained by multiplying the length into the breadth . Now , if the area and one side of any parallelo- gram be given , the other side may be found by dividing the area by the given side . So , also , if the area of a square be given ...
Page 28
... obtained by the following method : To find the area of a Triangle from the length of its sides . Rule.-I. Add together the lengths of the three sides , and take half their sum . II . From this half sum subtract each side separately ...
... obtained by the following method : To find the area of a Triangle from the length of its sides . Rule.-I. Add together the lengths of the three sides , and take half their sum . II . From this half sum subtract each side separately ...
Page 29
... obtain the products , we have 161x27x53x81 -18661671 : from which we find area = 18661671 , -4319 square rods . Ex . 2. What is the area of a triangle whose three sides are 52 , 39 and 65 feet ? Ans . 1014 sq . ft . An Isosceles ...
... obtain the products , we have 161x27x53x81 -18661671 : from which we find area = 18661671 , -4319 square rods . Ex . 2. What is the area of a triangle whose three sides are 52 , 39 and 65 feet ? Ans . 1014 sq . ft . An Isosceles ...
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A Practical System of Mensuration of Superficies and Solids: Designed ... J. M. Scribner No preview available - 2017 |
A Practical System of Mensuration of Superficies and Solids J. M. Scribner No preview available - 2022 |
A Practical System of Mensuration of Superficies and Solids: Designed ... J. M. Scribner No preview available - 2017 |
Common terms and phrases
12 feet 18 inches 20 feet 9 feet ABCD ABFD assumed cube avoirdupois axis base 26 breadth centre chord circle whose diameter Circular Sector circular segment circumfer circumference circumscribed contained convex surface Cube Root cubic feet cubic ft cubic inches cylinder cylindrical ring decimal diff divide the product ellipse ends entire surface equal extract the square feet 6 inches feet long find the area find the Solidity frustrum gallon half hypotenuse inner diameter inscribed square lateral surface length miles multiply the sum Nonagon number of degrees number of sides number of square OPERATION parabola parallel sides parallelogram pentagonal pyramid perpendicular distance perpendicular height plane prism PROBLEM radius regular pentagonal regular Polygon Required the area Required the solidity rhombus right angled triangle Rule Rule.-I slant height solid contents sphere spherical segment spheroid square feet square rods square root square yards thickness trapezium zoid zone
Popular passages
Page 53 - RULE. Find the area of the sector which has the same arc, and also the area of the triangle formed by the chord of the segment and the radii of the sector. Then...
Page 35 - Now, since the areas of similar polygons are to each other as the squares of their homologous sides...
Page 79 - A sphere is a solid terminated by a curved surface, all the points of which are equally distant from a point within called the centre.
Page 80 - A zone is a portion of the surface of a sphere included between two parallel planes.
Page 90 - ... to three times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by .5236 for the contents.
Page 49 - From 8 times the chord of half the arc subtract the chord of the whole arc, and ' of the remainder will be the length of the arc nearly.
Page 72 - RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity.
Page 51 - As 360 degrees is to the number of degrees in the arc of the sector, so is the area of the circle to the area of the sector.
Page 91 - From three times the diameter of the sphere subtract twice the height of the segment; multiply this remainder by the square of the height and the product by 0.5236.
Page 39 - A Circle is a plane figure bounded by a curve line, called the Circumference, which is everywhere equidistant from a certain point within, called its Centre.
Bibliographic information
| Title | A Practical System of Mensuration of Superficies and Solids ... |
| Author | J. M. Scribner |
| Publisher | H. & J. C. Ivison, 1844 |
| Original from | the University of Michigan |
| Digitized | 11 Jun 2007 |
| Length | 123 pages |
| Export Citation | BiBTeX EndNote RefMan |