A Practical System of Mensuration of Superficies and Solids ... |
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Page 26
... divide the number of square feet by the number of square feet in a piece , and the quotient will be the number of ... product will be the area . Or multiply half the side by the perpen- dicular . NOTE . In a right angled triangle ...
... divide the number of square feet by the number of square feet in a piece , and the quotient will be the number of ... product will be the area . Or multiply half the side by the perpen- dicular . NOTE . In a right angled triangle ...
Page 33
... divide the product by 2 for the area . And , 91698.97-2-45849.485 , Ans . Ex . 2. How many square rods are contained in a field which has two parallel sides , 65 and 38 rods , and whose breadth is 27 rods ? Ans . 139.05 . Ex . 3 ...
... divide the product by 2 for the area . And , 91698.97-2-45849.485 , Ans . Ex . 2. How many square rods are contained in a field which has two parallel sides , 65 and 38 rods , and whose breadth is 27 rods ? Ans . 139.05 . Ex . 3 ...
Page 36
... Multiply this sum by the base line , and divide the product by the number of equal parts of the base . Ex . 1. The breadths of an irregular figure , at five equi- distant places , being 8.2 , 7.4 , 9.2 , 10.2 , 8.6 , and the whole ...
... Multiply this sum by the base line , and divide the product by the number of equal parts of the base . Ex . 1. The breadths of an irregular figure , at five equi- distant places , being 8.2 , 7.4 , 9.2 , 10.2 , 8.6 , and the whole ...
Page 37
... divide their sum by the number of them , for the mean breadth ; then multiply the mean breadth by the length , and the product will be the whole area not far from the truth . PROMISCUOUS EXAMPLES . 1. What is the area of an equilateral ...
... divide their sum by the number of them , for the mean breadth ; then multiply the mean breadth by the length , and the product will be the whole area not far from the truth . PROMISCUOUS EXAMPLES . 1. What is the area of an equilateral ...
Page 41
... divide the product by 7. Or , Rule III . Multiply the diameter by 355 , and divide the product by 113 . NOTE . The learner may have the curiosity to enquire why we use the number 3,14159 . or 3,1416 , as is sometimes used , instead ...
... divide the product by 7. Or , Rule III . Multiply the diameter by 355 , and divide the product by 113 . NOTE . The learner may have the curiosity to enquire why we use the number 3,14159 . or 3,1416 , as is sometimes used , instead ...
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A Practical System of Mensuration of Superficies and Solids: Designed ... J. M. Scribner No preview available - 2017 |
A Practical System of Mensuration of Superficies and Solids J. M. Scribner No preview available - 2022 |
A Practical System of Mensuration of Superficies and Solids: Designed ... J. M. Scribner No preview available - 2017 |
Common terms and phrases
18 feet 18 inches 20 feet 9 feet ABCD ABFD assumed cube avoirdupois axis base 26 breadth chord circle whose diameter Circular Sector circular segment circumfer circumference circumscribed contained convex surface Cube Root cubic ft cubic inches cylinder cylindrical ring decimal diff divide the product ellipse ends entire surface equal extract the square feet 6 inches feet long find the area find the Solidity frustrum gallon half hypotenuse inner diameter inscribed square lateral surface miles Multiply the diameter Multiply the square multiply the sum Nonagon number of degrees number of sides number of square OPERATION parabola parallel sides parallelogram pentagonal pyramid perimeter perpendicular distance perpendicular height plane prism PROBLEM radius regular Polygon Required the area Required the solidity rhombus right angled triangle Rule Rule.-I Rule.-Multiply slant height solid contents sphere spherical segment spheroid square feet square rods square root square yards trapezium zoid zone
Popular passages
Page 53 - RULE. Find the area of the sector which has the same arc, and also the area of the triangle formed by the chord of the segment and the radii of the sector. Then...
Page 35 - Now, since the areas of similar polygons are to each other as the squares of their homologous sides...
Page 79 - A sphere is a solid terminated by a curved surface, all the points of which are equally distant from a point within called the centre.
Page 80 - A zone is a portion of the surface of a sphere included between two parallel planes.
Page 90 - ... to three times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by .5236 for the contents.
Page 49 - From 8 times the chord of half the arc subtract the chord of the whole arc, and ' of the remainder will be the length of the arc nearly.
Page 72 - RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity.
Page 51 - As 360 degrees is to the number of degrees in the arc of the sector, so is the area of the circle to the area of the sector.
Page 91 - From three times the diameter of the sphere subtract twice the height of the segment; multiply this remainder by the square of the height and the product by 0.5236.
Page 39 - A Circle is a plane figure bounded by a curve line, called the Circumference, which is everywhere equidistant from a certain point within, called its Centre.