A Practical System of Mensuration of Superficies and Solids ... |
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Page ix
... CIRCLE AND ITS PARTS , General Principles , ... Circumference of a Circle ,. Diameter of a Circle , .. Area of a Circle ,. Page . 9-15 16 17 17-23 23-26 26 27-32 32-33 33 34-36 36-38 39 .. 39-41 41-42 Length of an Arc of a Circle ...
... CIRCLE AND ITS PARTS , General Principles , ... Circumference of a Circle ,. Diameter of a Circle , .. Area of a Circle ,. Page . 9-15 16 17 17-23 23-26 26 27-32 32-33 33 34-36 36-38 39 .. 39-41 41-42 Length of an Arc of a Circle ...
Page 39
... circle . 1 D A B E 2. A Diameter of a circle is a straight line , passing through the centre and terminating at the circumference ; as AB ( fig . 1. ) 3. A Radius or Semi - Diameter is a straight line , extend- ing from the centre to the ...
... circle . 1 D A B E 2. A Diameter of a circle is a straight line , passing through the centre and terminating at the circumference ; as AB ( fig . 1. ) 3. A Radius or Semi - Diameter is a straight line , extend- ing from the centre to the ...
Page 41
... diameter is given . ART . 16. Rule I. - Multiply the diameter by 3.14159 , and the product will be the circumference . Or , Rule II . As 7 : 22 diameter to the circumference ; that is , Multiply the ... Circumference of a Circle, 41-42.
... diameter is given . ART . 16. Rule I. - Multiply the diameter by 3.14159 , and the product will be the circumference . Or , Rule II . As 7 : 22 diameter to the circumference ; that is , Multiply the ... Circumference of a Circle, 41-42.
Page 42
... whose diameter EF is 24 feet ? E In this operation we sim- ply multiply the diameter , 24 , by the number 3.14159 , and the product gives the circumference . OPERATION . 24x3.14159-75.39816 , which is ... Diameter of a Circle 42 MENSURATION.
... whose diameter EF is 24 feet ? E In this operation we sim- ply multiply the diameter , 24 , by the number 3.14159 , and the product gives the circumference . OPERATION . 24x3.14159-75.39816 , which is ... Diameter of a Circle 42 MENSURATION.
Page 43
J. M. Scribner. PROBLEM II . To find the Diameter of a Circle when the circumference is given . ART . 17. Rule I ... whose circum- ference is 146.084 ? Ans . 46.5 . Ex . 4. What is the diameter of the Moon if her circum- ference be 6850 ...
J. M. Scribner. PROBLEM II . To find the Diameter of a Circle when the circumference is given . ART . 17. Rule I ... whose circum- ference is 146.084 ? Ans . 46.5 . Ex . 4. What is the diameter of the Moon if her circum- ference be 6850 ...
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A Practical System of Mensuration of Superficies and Solids: Designed ... J. M. Scribner No preview available - 2017 |
A Practical System of Mensuration of Superficies and Solids J. M. Scribner No preview available - 2022 |
A Practical System of Mensuration of Superficies and Solids: Designed ... J. M. Scribner No preview available - 2017 |
Common terms and phrases
12 feet 18 inches 20 feet 9 feet ABCD ABFD assumed cube avoirdupois axis base 26 breadth centre chord circle whose diameter Circular Sector circular segment circumfer circumference circumscribed contained convex surface Cube Root cubic feet cubic ft cubic inches cylinder cylindrical ring decimal diff divide the product ellipse ends entire surface equal extract the square feet 6 inches feet long find the area find the Solidity frustrum gallon half hypotenuse inner diameter inscribed square lateral surface length miles multiply the sum Nonagon number of degrees number of sides number of square OPERATION parabola parallel sides parallelogram pentagonal pyramid perpendicular distance perpendicular height plane prism PROBLEM radius regular pentagonal regular Polygon Required the area Required the solidity rhombus right angled triangle Rule Rule.-I slant height solid contents sphere spherical segment spheroid square feet square rods square root square yards thickness trapezium zoid zone
Popular passages
Page 53 - RULE. Find the area of the sector which has the same arc, and also the area of the triangle formed by the chord of the segment and the radii of the sector. Then...
Page 35 - Now, since the areas of similar polygons are to each other as the squares of their homologous sides...
Page 79 - A sphere is a solid terminated by a curved surface, all the points of which are equally distant from a point within called the centre.
Page 80 - A zone is a portion of the surface of a sphere included between two parallel planes.
Page 90 - ... to three times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by .5236 for the contents.
Page 49 - From 8 times the chord of half the arc subtract the chord of the whole arc, and ' of the remainder will be the length of the arc nearly.
Page 72 - RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity.
Page 51 - As 360 degrees is to the number of degrees in the arc of the sector, so is the area of the circle to the area of the sector.
Page 91 - From three times the diameter of the sphere subtract twice the height of the segment; multiply this remainder by the square of the height and the product by 0.5236.
Page 39 - A Circle is a plane figure bounded by a curve line, called the Circumference, which is everywhere equidistant from a certain point within, called its Centre.
Bibliographic information
| Title | A Practical System of Mensuration of Superficies and Solids ... |
| Author | J. M. Scribner |
| Publisher | H. & J. C. Ivison, 1844 |
| Original from | the University of Michigan |
| Digitized | 11 Jun 2007 |
| Length | 123 pages |
| Export Citation | BiBTeX EndNote RefMan |