A Practical System of Mensuration of Superficies and Solids ... |
From inside the book
Results 1-5 of 47
Page 23
... Rule . - Multiply the length by the breadth or perpendicular height , and the product will be the area . It is manifest that the number D of square inches in the parallelo- gram ABCD is equal to the num- ber of linear inches in the ...
... Rule . - Multiply the length by the breadth or perpendicular height , and the product will be the area . It is manifest that the number D of square inches in the parallelo- gram ABCD is equal to the num- ber of linear inches in the ...
Page 26
... Rule . - Multiply the length of one of the sides by the perpendicular falling upon it , and half the product will be the area . Or multiply half the side by the perpen- dicular . NOTE . In a right angled triangle the longest side is ...
... Rule . - Multiply the length of one of the sides by the perpendicular falling upon it , and half the product will be the area . Or multiply half the side by the perpen- dicular . NOTE . In a right angled triangle the longest side is ...
Page 28
... Rule.-I. Add together the lengths of the three sides , and take half their sum . II . From this half sum subtract each side separately . III . Multiply together the half sum and each of the three remainders , and extract the square root ...
... Rule.-I. Add together the lengths of the three sides , and take half their sum . II . From this half sum subtract each side separately . III . Multiply together the half sum and each of the three remainders , and extract the square root ...
Page 33
... Rule . - Multiply the sum of the two parallel sides by the perpendicular distance between them , and half the product will be the area . Ex . 1. Required the area of the trape- zoid ABCD , having given AB = 321.51 feet , DC - 214.24 ...
... Rule . - Multiply the sum of the two parallel sides by the perpendicular distance between them , and half the product will be the area . Ex . 1. Required the area of the trape- zoid ABCD , having given AB = 321.51 feet , DC - 214.24 ...
Page 34
... Rule I. - Multiply one of its sides into half its perpendicular distance from the centre , and this product into the number of sides . It is evident , on inspection , that a regu- lar polygon contains as many equal trian- gles as the ...
... Rule I. - Multiply one of its sides into half its perpendicular distance from the centre , and this product into the number of sides . It is evident , on inspection , that a regu- lar polygon contains as many equal trian- gles as the ...
Other editions - View all
A Practical System of Mensuration of Superficies and Solids: Designed ... J. M. Scribner No preview available - 2017 |
A Practical System of Mensuration of Superficies and Solids J. M. Scribner No preview available - 2022 |
A Practical System of Mensuration of Superficies and Solids: Designed ... J. M. Scribner No preview available - 2017 |
Common terms and phrases
12 feet 18 inches 20 feet 9 feet ABCD ABFD assumed cube avoirdupois axis base 26 breadth centre chord circle whose diameter Circular Sector circular segment circumfer circumference circumscribed contained convex surface Cube Root cubic feet cubic ft cubic inches cylinder cylindrical ring decimal diff divide the product ellipse ends entire surface equal extract the square feet 6 inches feet long find the area find the Solidity frustrum gallon half hypotenuse inner diameter inscribed square lateral surface length miles multiply the sum Nonagon number of degrees number of sides number of square OPERATION parabola parallel sides parallelogram pentagonal pyramid perpendicular distance perpendicular height plane prism PROBLEM radius regular pentagonal regular Polygon Required the area Required the solidity rhombus right angled triangle Rule Rule.-I slant height solid contents sphere spherical segment spheroid square feet square rods square root square yards thickness trapezium zoid zone
Popular passages
Page 53 - RULE. Find the area of the sector which has the same arc, and also the area of the triangle formed by the chord of the segment and the radii of the sector. Then...
Page 35 - Now, since the areas of similar polygons are to each other as the squares of their homologous sides...
Page 79 - A sphere is a solid terminated by a curved surface, all the points of which are equally distant from a point within called the centre.
Page 80 - A zone is a portion of the surface of a sphere included between two parallel planes.
Page 90 - ... to three times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by .5236 for the contents.
Page 49 - From 8 times the chord of half the arc subtract the chord of the whole arc, and ' of the remainder will be the length of the arc nearly.
Page 72 - RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity.
Page 51 - As 360 degrees is to the number of degrees in the arc of the sector, so is the area of the circle to the area of the sector.
Page 91 - From three times the diameter of the sphere subtract twice the height of the segment; multiply this remainder by the square of the height and the product by 0.5236.
Page 39 - A Circle is a plane figure bounded by a curve line, called the Circumference, which is everywhere equidistant from a certain point within, called its Centre.