A Practical System of Mensuration of Superficies and Solids ... |
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Page 17
... problems in the fol- lowing work . The surfaces or capacities of regular solids are readily calculated , but more intricacy attends the calculations of the surfaces and solid contents of many irregular bodies , as of frustrums , of ...
... problems in the fol- lowing work . The surfaces or capacities of regular solids are readily calculated , but more intricacy attends the calculations of the surfaces and solid contents of many irregular bodies , as of frustrums , of ...
Page 21
... problem in the mensuration of super- ficies , is the very simple one of determining the area of a right parallelogram , as has been shown above . The con- tents of other figures may readily be obtained by finding parallelograms which ...
... problem in the mensuration of super- ficies , is the very simple one of determining the area of a right parallelogram , as has been shown above . The con- tents of other figures may readily be obtained by finding parallelograms which ...
Page 23
... problems . PROBLEM I. To find the area of a Four - sided Figure , whether it be a par- allelogram , square , rhombus , or rhomboid . ART . 4. Rule . - Multiply the length by the breadth or perpendicular height , and the product will be ...
... problems . PROBLEM I. To find the area of a Four - sided Figure , whether it be a par- allelogram , square , rhombus , or rhomboid . ART . 4. Rule . - Multiply the length by the breadth or perpendicular height , and the product will be ...
Page 26
... PROBLEM II . To find the area of a Triangle . Ans . 13 . A RT.6 . Rule . - Multiply the length of one of the sides by the perpendicular falling upon it , and half the product will be the area . Or multiply half the side by the perpen ...
... PROBLEM II . To find the area of a Triangle . Ans . 13 . A RT.6 . Rule . - Multiply the length of one of the sides by the perpendicular falling upon it , and half the product will be the area . Or multiply half the side by the perpen ...
Page 32
... PROBLEM III . To find the area of a Trapezium . ART . 11. Rule . - Divide the trapezium into triangles by drawing diagonals ; and the sum of the areas of these tri- angles will be the area of the trapezium . Ex . 1. In the irregular ...
... PROBLEM III . To find the area of a Trapezium . ART . 11. Rule . - Divide the trapezium into triangles by drawing diagonals ; and the sum of the areas of these tri- angles will be the area of the trapezium . Ex . 1. In the irregular ...
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A Practical System of Mensuration of Superficies and Solids: Designed ... J. M. Scribner No preview available - 2017 |
A Practical System of Mensuration of Superficies and Solids J. M. Scribner No preview available - 2022 |
A Practical System of Mensuration of Superficies and Solids: Designed ... J. M. Scribner No preview available - 2017 |
Common terms and phrases
12 feet 18 inches 20 feet 9 feet ABCD ABFD assumed cube avoirdupois axis base 26 breadth centre chord circle whose diameter Circular Sector circular segment circumfer circumference circumscribed contained convex surface Cube Root cubic feet cubic ft cubic inches cylinder cylindrical ring decimal diff divide the product ellipse ends entire surface equal extract the square feet 6 inches feet long find the area find the Solidity frustrum gallon half hypotenuse inner diameter inscribed square lateral surface length miles multiply the sum Nonagon number of degrees number of sides number of square OPERATION parabola parallel sides parallelogram pentagonal pyramid perpendicular distance perpendicular height plane prism PROBLEM radius regular pentagonal regular Polygon Required the area Required the solidity rhombus right angled triangle Rule Rule.-I slant height solid contents sphere spherical segment spheroid square feet square rods square root square yards thickness trapezium zoid zone
Popular passages
Page 53 - RULE. Find the area of the sector which has the same arc, and also the area of the triangle formed by the chord of the segment and the radii of the sector. Then...
Page 35 - Now, since the areas of similar polygons are to each other as the squares of their homologous sides...
Page 79 - A sphere is a solid terminated by a curved surface, all the points of which are equally distant from a point within called the centre.
Page 80 - A zone is a portion of the surface of a sphere included between two parallel planes.
Page 90 - ... to three times the square of the radius of the segment's base, add the square of its height ; then multiply the sum by the height, and the product by .5236 for the contents.
Page 49 - From 8 times the chord of half the arc subtract the chord of the whole arc, and ' of the remainder will be the length of the arc nearly.
Page 72 - RULE.* To the sum of the areas of the two ends add four times the area of a section parallel to and equally distant from both ends, and this last sum multiplied by £ of the height will give the solidity.
Page 51 - As 360 degrees is to the number of degrees in the arc of the sector, so is the area of the circle to the area of the sector.
Page 91 - From three times the diameter of the sphere subtract twice the height of the segment; multiply this remainder by the square of the height and the product by 0.5236.
Page 39 - A Circle is a plane figure bounded by a curve line, called the Circumference, which is everywhere equidistant from a certain point within, called its Centre.
Bibliographic information
| Title | A Practical System of Mensuration of Superficies and Solids ... |
| Author | J. M. Scribner |
| Publisher | H. & J. C. Ivison, 1844 |
| Original from | the University of Michigan |
| Digitized | 11 Jun 2007 |
| Length | 123 pages |
| Export Citation | BiBTeX EndNote RefMan |