| George Washington Hull - Geometry - 1807 - 408 pages
...PROPOSITION XI. THEOREM. 531. The lateral area, of a frustum of a cone of revolution is equal to one half of the sum of the circumferences of its bases multiplied by its slant height. Given — S the lateral area, C and c the circumferences of the bases, and L the slant height of a frustum... | |
| William Chauvenet - Geometry - 1871 - 380 pages
...altitudes, or as the squares of the radii of their bases. /"r\ -.vA-.y PROPOSITION VI.— THEOREM. >.. 26. The lateral area of a frustum of a cone of revolution is equal to the half sum of the circumferences of its bases multiplied by its slant height. The plane which cuts... | |
| Charles Davies - Geometry - 1872 - 464 pages
...and its slant height is equal to that of the cone: hence, the convex surface of the frustum of a cone is equal to half the sum of the circumferences of its bases multiplied by the slant height; which was to be proved. Scholium. From the extremities A and Z>, and from the middle... | |
| William Chauvenet - Geometry - 1872 - 382 pages
...of their altitudes, or as the squares of the radii of their bases. PROPOSITION VI.— THEOREM. 26. The lateral area of a frustum of a cone of revolution is equal to the half sum of the circumferences of its bases multiplied by its slant height. The plane which cuts... | |
| Adrien Marie Legendre - Geometry - 1874 - 500 pages
...its slant height is equal to that of the cone : hence, the convex surface of the frustum of a cone is equal to half the sum of the circumferences of its bases multiplied by the slant height ; which was to be proved. Scholium. From the extremities A and D, and from the middle... | |
| 1876 - 646 pages
...are mutually equiangular they are also mutually equilateral ; and are either equal or symmetrical. 8. The lateral area of a frustum of a cone of revolution is equal to the half sum of the circumferences of its bases multiplied by its slant height. ENGLISH GRAMMAR. JUNE,... | |
| William Guy Peck - Conic sections - 1876 - 376 pages
...a frustum of a right pyramid, whose bases are regular polygons having an infinite number of sides. half the sum of the circumferences of its bases multiplied by its slant height, (P. 4, Cor., B. 7). Cor. 3. The volume of a conic frustum is equal to the sum of its bases ph1s a mean... | |
| George Albert Wentworth - Geometry - 1877 - 416 pages
...frustum of a cone of revolution. Draw CHI-, and AD II, to YY'. Then area AB = AB X 2 jr СH, §662 (the lateral area of a frustum of a cone of revolution is equal to the slant height multiplied 'by the circumference of a section equidistant from its bases). The AABD... | |
| F. B. Stevens - Examinations - 1884 - 202 pages
...mutually equiangular, they are also mutually equilateral ; and are either equal or symmetrical. 8. The lateral area of a frustum of a cone of revolution is equal to the half sum of the circumferences of its bases multiplied by its slant height. June, 1882. NOTE 1.... | |
| Charles Davies, Adrien Marie Legendre - Geometry - 1885 - 538 pages
...its slant height is equal to that of the cone : hence, the convex surface of the frustum of a cone is equal to half the sum of the circumferences of its bases multiplied by its slant height ; which was to be proved. • Scholium. From the extremities A and D, and from the middle point I,... | |
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