 | Euclid, John Keill - Geometry - 1723 - 436 pages
...Angle HAC is alfo equal to the Angle MDF. Therefore the two Triangles MDF, HAC, have two Angles of the one equal to two Angles Of the other, each to each, and one Side of the one equal to one Side of the other, viz. that which is fubtended by one of the equal... | |
 | Euclid, John Keill - Geometry - 1733 - 446 pages
...Angle HAG is alfo equa to the Angle MDF. Therefore the two Triangles MDF, HA C, have two Angles of the one equal to two Angles of the other, each to each, and one Side of the one equal to one Side of the other, viz. that which is fubtended by one of the equal... | |
 | Robert Simson - Trigonometry - 1762 - 488 pages
...HCF is equal to KCF, and the right angle FHC equal to the right angle FKC ; in the triangles FHC, FKC there are two angles of one equal to two angles of the other ; and the fide FC, which is oppofite to one of the equal angles in each, is common to both ; therefore... | |
 | Euclid - Geometry - 1765 - 492 pages
...Clavius has alfo tranflated them into Latin. PROP. XXVI. THEO R. If two triangles have two angles of the one equal to two angles of the other, each to each, and one fide of the one equal to one fide of the other, either that fide which is hetween the equal angles,... | |
 | Robert Simson - Trigonometry - 1775 - 534 pages
...HCF is equal to KCF, and the right angle FHC equal to the right angle FKC; in the triangles FHC, FKC there are two angles of one equal to two angles of the other, and the fide FC, which is oppofite to one of the equal angles in each, is common to both ; therefore... | |
 | Euclid - Geometry - 1776 - 326 pages
...EDF, it muft be greater. Wherefore, &c. PROP. XXVI. THEO R. TF two triangles have two angles of the one equal to two angles •*• of the other, each to each, and aJiJe of the one equal to ajide of the other, either thejide lying between the equal angks, orj'ubtending... | |
 | Robert Simson - Trigonometry - 1781 - 534 pages
...CFD double of CFL i therefore the angle KFC is equal to th< -rr angle CFL ; and the right angi« \ FCK is equal to the right angle FCL. therefore in...to two angles of the other, each to each, and the fide FC, which is adjacent to the equal angles in each, is common to both ; therefore the other fides... | |
 | Euclid - 1781 - 552 pages
...Fl angle FCK is equal to the right angle FCL : Therefore, in the two triangles FKC, FLC, there ate two angles of one equal to two angles of the other, each t» each, and the fide FC, which is adjacent to the equal angles in each, is common to both ; theiefore... | |
 | Benjamin Donne - 1796 - 120 pages
...remaining angle of me nwji be equal to the remaining angle of the other. THEOREM 15. If two triangles have two angles of one equal to two angles of the other, each to each, and one s1de of one equal to one D side side of the other, the triangles are equal in every refpcEl. —... | |
 | Alexander Ingram - Trigonometry - 1799 - 374 pages
...Cv.ED 84. i. b 34. i. PROP. BooK I. 54.i, PROP. XXVI. THEOR. TF two triangles have two angles of the one equal to -*- two angles of the other, each to each ; and one fide equal to one fide, viz. either the fides adjacent to the equal angles, or the fides oppofite... | |
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If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal... 
