The millwright & engineer's pocket companion

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Page 81 - ... one of the most important, and at the same time, one of the least expensive and troublesome, which we possess.
Page 64 - The areas of circles are to each other as the squares of their diameters.
Page 34 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 73 - To find the solidity of a spheroid. RULE. — Multiply the square of the revolving axis by the fixed axis, and by .5236, and the product will be the solidity.
Page 64 - Area of a circle is equal to the area of a triangle whose base equals the circumference and perpendicular equals the radius.
Page 53 - Of four-sided figures, a square is that which has all its sides equal, and all its angles right angles.
Page 217 - RULE. — Multiply the difference between the root of the integer part of the given number, and the root of the next higher integer number, by the decimal part of the given number, and add the product to the root of the integer number given, the sum is the root required.
Page 94 - These simple machines are the lever, the wheel and axle, the pulley, the inclined plane, the wedge, and the screw.
Page 59 - NOTE. — 1. As 7 is to 22, so is the diameter to the circumference; or, as 22 is to 7, so is the circumference to the diameter.
Page 64 - As 355 : 452, or as 1 : 1,273239 : : so is the area : to the square of the diameter ; — or, multiply the square root of the area by 1,12837, and the product will be the diameter.

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