 | Adrien Marie Legendre - Geometry - 1819 - 574 pages
...the angle BAD = DAC, and the angle BDA = ADC. Consequently the two last are right angles ; therefore, the arc drawn from the vertex of an isosceles spherical triangle to the middle of the base, is perpendicular lo this base, and divides the angle opposite into two equal parts.... | |
 | Adrien Marie Legendre - Geometry - 1822 - 394 pages
...demonstration proves the angle BAD=DAC, and the angle BDA=ADC. Hence the two 172 last are right angles ; hence the arc drawn from the vertex of an isosceles spherical triangle to the middle of the base, is at right angles to that base, and bisects the opposite angle. PROPOSITION XVI.... | |
 | Adrien Marie Legendre, John Farrar - Geometry - 1825 - 294 pages
...angle BAD — DAC, and the angle BDA = ADC. Consequently the two last are right angles ; therefore, the arc drawn from the vertex of an isosceles spherical triangle to the middle of the base, is perpendicular to this base, and divides the angle opposite into two equal parts.... | |
 | Adrien Marie Legendre, John Farrar - Geometry - 1825 - 280 pages
...the angle BAD - DAC, and the angle BDA = ADC. Consequently the two last are right angles; therefore, the arc drawn from the vertex of an isosceles spherical triangle to ihe middle of the base, is perpendicular to this base, and divides the angle opposite into two equal... | |
 | Adrien Marie Legendre - Geometry - 1825 - 276 pages
...the angle BAD - DAC, and the angle BDA = ADC. Consequently the two last are right angles ; therefore, the arc drawn from the vertex of an isosceles spherical triangle to ihe middle of the base, is perpendicular to this base, and divides the angle opposite into two equal... | |
 | Adrien Marie Legendre - Geometry - 1836 - 394 pages
...demonstration proves the angle BAD = DAC, and the angle BDA— ADC. Hence the two last are right angles ; hence the arc drawn from the vertex of an isosceles spherical triangle to the middle of the base, is at right angles to that base, and bisects the vertical angle. PROPOSITION XIV.... | |
 | Benjamin Peirce - Geometry - 1837 - 216 pages
...Corollary. Also the angle ADB = ADC, and, therefore, each is a right angle ; and also DAB = DAC, that . is> The arc, drawn from the vertex of an isosceles spherical triangle to the middle of the base, is perpendicular to the base, and bisects the angle at the vertex. 454. Corollary.... | |
 | Adrien Marie Legendre - Geometry - 1841 - 288 pages
...angle BAD = DAC, and the angle BDA — ADC. Consequently the two last are right angles ; therefore, the arc drawn from the vertex of an isosceles spherical triangle to the middle of the base, is perpendicular to this base, and divides the angle opposite into two equal parts.... | |
 | Nathan Scholfield - Conic sections - 1845 - 542 pages
...demonstration proves the angle BAD =DAC, and the angle BDA— ADC. Hence the two last are right angles ; hence the arc drawn from the vertex of an isosceles spherical triangle to the middle of the base, is at right angles to the base, and bisects the vertical angle. PROPOSITION XVI.... | |
 | Nathan Scholfield - Conic sections - 1845 - 244 pages
...demonstration proves the angle BAD =DAC, and the angle BDA=ADC. Hence the two last are right angles ; hence the arc drawn from the vertex of an isosceles spherical triangle to the middle of the base, is at right angles to the base, and bisects the vertical angle. PROPOSITION XVI.... | |
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In any spherical triangle, the greater side is opposite the greater angle ; and conversely, the greater angle is opposite the greater side. 
