 | William Ruger - Arithmetic - 1832 - 282 pages
...tiplying the second term by the ra\ tio, and so on; hence it is obvious Ans. or 9th term. 26244 that the ratio raised to a power one less than the number of terms, and 1liat power multiplied by the first term, mast give the last term, because the same multipliers... | |
 | Calvin Tracy - Arithmetic - 1840 - 326 pages
...or factor, eleven times ; that is, any term of a series is equal to the first term multiplied by the ratio raised to a power one less than the number of terms. Thus, 2 x 3 x 3 x 3x3x3x3x3x3x3x3x3" = 3x2= 354294, Ans. or twelfth term. . , 2. A person purchased... | |
 | William Ruger - Arithmetic - 1841 - 268 pages
...tiplying the second term by the ratio, and so on ; hence it is obvious, Ans. or 9th term, 26244 that the ratio raised to a power one less than the number of terms, and thai power multiplied by the first term, must give the last term, because the same multipliers... | |
 | Francis Henney Smith - Arithmetic - 1845 - 300 pages
...100, 20, 4 1 237* From the manner in which an increasing geometrical series is formed, we see that 3d term = 1st term multiplied by the common ratio. 3d...term, 3 the OPERATION. common ratio, and the .number 1 X 36 =1 X 243=243. of terms six, the sixth term will be equal to the first term 1, multiplied by... | |
 | Daniel Adams - Arithmetic - 1848 - 330 pages
...ratio of an increasing series are given, to find the last term, RULE. Multiply the first term by the ratio raised to a power one less than the number of terms. NOTE 1 . — To get a high power of a number, it is convenient to write down a few of tha lower powers,... | |
 | Daniel Adams - Arithmetic - 1848 - 342 pages
...ratio of an increasing series are given, to find the last term, RULE:. Multiply the first term by the ratio raised to a power one less than the number of terms. NOTE 1. — To get a high power of a number, it is convenient to write down B few of'the lower powers, and... | |
 | Daniel Adams - Arithmetic - 1848 - 322 pages
...ratio of an increasing series are given, to find the last term, RULE. Multiply the first term by the ratio raised to a power one less than the number of terms. NOTE 1 . — To get a high power of a number, it is convenient to write dowu a few of the lower powers,... | |
 | Silas Lawrence Loomis - Arithmetic - 1859 - 324 pages
...LAST TERM, RATIO, AND NUMBER OF TERMS, TO FIND THE FIRST TERM. RULE. — Divide the last term by the ratio, raised to a power one less than the number of terms. PROB. CLXI. — GIVEN, THE EXTREMES AND RATIO, TO FIND THE SUM OF THE SERIES. RULE. — Divide the... | |
 | Daniel Adams - Arithmetic - 1861 - 452 pages
...ratio of an increasing series are given, to find the last term, RUX.S. Multiply the first term by the ratio raised to a power one less than the number of terms. To get a high power of a number, it is convenient to write down a few of the lower powers, and multiply... | |
 | George Heppel - 1864 - 234 pages
...first multiplied by 27, or 3 3 , and so on, any term being equal to the product of the first term and the common ratio raised to a power one less than the number of terms. Thus, the 9th term of the series is 7 x3 8 =45927. Again, the 12th. term of the series, 56, 28, 14.... | |
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Hence, when the first term, number of terms, and ratio of an increasing series are give?i, to find the last term, RULE!. Multiply the first term by the ratio raised to a power one less than the number of terms. NOTE 1. 
