 | Isaac Newton, Edmond Halley - Algebra - 1720 - 312 pages
...promoting Algebraick Calculus) to find the Segments of the Bafe ; here it would be of Ufe to know, that the Difference of the Squares of the Sides is equal to the double Rc£hngle under the Bafe, and the Diftance of the Perpendicular from the Middle of the Bails.... | |
 | Isaac Newton - Algebra - 1769 - 638 pages
...promoting algebraick Calculus) to find the Segments of the Bafe; here it would be of Ufe to know, that the Difference of the Squares of the Sides is equal to the double Rettangle under the Bafe, and the Difame of the Perpendicular from the Middle ef the Softs (k).... | |
 | Thomas Malton - 1774 - 484 pages
...Angle, added to the Squares of the alternate Segments of the Bafe, are equal; and the difference between the Squares of the Sides, is equal to the difference of the Squares of the Segr ments. In Ifofceles Triangles the thing is manifctt. In the Scalene Triangle ABC, draw the Perpendicular... | |
 | W. Hilton - Science - 1797 - 308 pages
...AL.LB. qED PROP. 11. • .» PROP. 11. BV N. Sim. The rectangle of the segments of the diameter HD.D£ is equal to the difference of the squares of the segments of the base EK,EL. • DEMONS. HD.DF^rDCJ=EK!,butHD.DF=HD.DE -f HD.EF, therefore HD.DE=EK'-HD.EF=EK2-EL' T/iro/t.... | |
 | John Playfair - Mathematics - 1806 - 320 pages
...other. PROP. C. THEOR. IF a perpendicular be drawn from any angle of a triangle to the opposite side, the difference of the squares of the sides is equal...difference of the squares of the segments of the base. Book IT. Let ABC be a. triangle, having the side AB greater than AC, and AD a perpendicular from the... | |
 | Charles Hutton - Mathematics - 1812 - 620 pages
...and the triangles Identical. THEOREM XXXV. IN any Triangle, the Difference of the Squares of the two Sides, is Equal to the Difference of the Squares of the Segments of the Base, or of the two Lines, or Distances, included between the Extremes of the Base and the Perpendicular.... | |
 | Charles Hutton - Mathematics - 1816 - 610 pages
...and the triangles identical. THEOREM XXXV. IN any Triangle, the Difference of the Squares of the two Sides, is Equal to the Difference of the Squares of the Segments of the Babe, or of the two Lines, or Distances, included between the Extremes of the Base and the Perpendicular.... | |
 | Miles Bland - Euclid's Elements - 1819 - 444 pages
...the square AC. (29.) In any triangle if a line be drawn from the vertex at right angles to the base, the difference of the squares of the sides is equal...difference of the squares of the segments of the base. S From A the vertex of the triangle ABC, let AD be drawn perpendicular to the base ; the difference... | |
 | Miles Bland - Euclid's Elements - 1819 - 442 pages
...the square AC. (29.) In any triangle if a line be drawn from the vertex at right angles to the base, the difference of the squares of the sides is equal to the difference of tlie squares of the segments of the base. . « From A the vertex of the triangle ABC, let AD be drawn... | |
 | Miles Bland - Geometry - 1821 - 898 pages
...the square AC. (29.) In any triangle if a line be drawn from the vertex at right angles to the base ; the difference of the squares of the sides is equal to the difference of t/i" squares of the segments of the base. From A the vertçxof the triangle ABC, let AD be drawn perpendicular... | |
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If a perpendicular be drawn from the vertical angle of any triangle to the base, the difference of the squares of the sides is equal to the difference of the squares of the segments of the base. 
