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adjacent altitude axis base called centre circle circumscribed coincide common cone conical containing convex COROLLARY cube cuboid curve cylinder DEFINITION determined diagonal diameter dihedral angle distance divided edges element equal equal respectively equivalent EXERCISES face angles figure find the volume fixed frustum geometry given greater half height hence homologous inscribed intersection lateral edges length less lies limit line of intersection lune measure meet namely normal opposite sides pair parallel lines parallelepiped parallelogram passes perpendicular plane angle plane section plane ẞ pole polygon polyhedron portion prism projection proposition proved pyramid quadrants radius ratio regular respectively right circular cone sides similar solid space sphere spherical triangle square straight line surface taken tangent tetrahedron THEOREM third three sides triangular trihedral vertex vertices volume
Page 80 - An oblique prism is equivalent to a right prism whose base is a right section of the oblique prism, and whose altitude is equal to a lateral edge of the oblique prism. Hyp. OM is a right section of oblique prism AD', and OM ' a right prism whose altitude is equal to a lateral edge of AD'. To prove AD' =0= GM' . Proof. The lateral edges of GM
Page 111 - A sphere is a solid bounded by a curved surface, every point of which is equally distant from a point within called the center.
Page 49 - Find a point in a given straight line such that the sums of its distances from two given points (not in the same plane with the given straight line) may be the least possible.
Page 141 - If two triangles have two angles, and the included side of the one equal to two angles and the included side of the other, each to each, the two triangles will be equal...
Page 141 - If two triangles have two sides of the one equal respectively to two sides of the other, but the included angle of the first greater than the included angle of the second, then the third side of the first is greater than the third side of the second. Given A ABC and A'B'C...