 | William Scott - Algebra - 1844 - 568 pages
...figure of the root) to the first figure, and also to the divisor. Multiply the new divisor thus formed by the second figure of the root, and subtract the product from the number composed of the first remainder and second period. To this, the second remainder, annex the... | |
 | Francis Henney Smith - Arithmetic - 1845 - 710 pages
...figure of the root. IV. Place it in the root, and also on the right of the divisor. Multiply the entire divisor by the second figure of the root, and subtract the product from the dividend. To the remainder bring down the next period. V. Double the whole of the root found for a... | |
 | Francis Henney Smith - Arithmetic - 1845 - 300 pages
...figure of the root. IV. Place it in the root, and also on the right of the divisor. Multiply the entire divisor by the second figure of the root, and subtract the product from the dividend. To the remainder bring down the next period. V; Double the whole of the root found for a... | |
 | Charles Davies - Algebra - 1845 - 382 pages
...first figure of the root and the sum ; in the last column will be the second divisor, which multiply by the second figure of the root and subtract the product from the second dividend. V. Tlie next trial divisor, the, next figure of the root, and the true divisor, are... | |
 | William Scott - Arithmetic - 1854 - 232 pages
...root) to the first figure of the root, and also to the divisor. Multiply the new divisor, thus formed, by the second figure of the root, and subtract the product from the number composed of the first remainder and second period. To this remainder annex the third period... | |
 | James Stewart Eaton - Arithmetic - 1857 - 376 pages
...root and also at the right of the trial divisor, and so form the TRUE DIVISOR. 5. Multiply the true divisor by the second figure of the root and subtract the product from the dividend. 6. To the remainder annex the next period for a new dividend, and, having doubled the part... | |
 | Steam-engines - 1865 - 580 pages
...4800, and add them together. The resulting sum, 5169, is the first real divisor. We next multiply the divisor by the second figure of the root, and subtract the product 15507, as in long division, bringing down the next period 568. To obtain the next real divisor we proceed... | |
 | John Fair Stoddard - Arithmetic - 1868 - 428 pages
...the second, also the square of the second, and the sum will be the TRUE DIVISOE. 5. Multiply the true divisor by the second figure of the root, and subtract the product from the dividend, and bring down the next period for a 2d DIVIDEND. 6. Take 300 times the square of the figures... | |
 | John Fair Stoddard - Arithmetic - 1888 - 480 pages
...x 10=12000, and 10"=100 to the trial divisor for the true divisor. Multiply the true divisor by 10, the second figure of the root, and subtract the product from the first dividend. The remainder will be the 2d dividend. Take 3 times the square of 410 for a trial divisor.... | |
 | John Bourne - Steam-engines - 1873 - 508 pages
...4800, and add them together. The resulting sum, 5169, is the first real divisor. We next multiply the divisor by the second figure of the root, and subtract the product 15507, as in long division, bringing down the next period 568. To obtain the next real divisor we proceed... | |
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Multiply the complete divisor by the second figure of the root and subtract the product from the dividend. 
