## The Elements of Euclid; viz. the first six books, together with the eleventh and twelfth. Also the book of Euclid's Data. By R. Simson. To which is added, A treatise on the construction of the trigonometrical canon [by J. Christison] and A concise account of logarithms [by A. Robertson].1814 |

### From inside the book

Results 1-5 of 99

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**point**C , in which the circles cut one another , draw the straight lines CA , Book I. 3 Postu- late . 1 Post . CB ...**F**; from the centre B , at the distance BC described the circle CGH , and from the centre D , at the distance DG ... Page 9

... point B shall coincide with the point E , because AB is equal to DE ; and AB coinciding with DE , AC shall coin- cide with DF , because the angle BAC is equal to the angle EDF ; wherefore also the point C shall coincide with the

... point B shall coincide with the point E , because AB is equal to DE ; and AB coinciding with DE , AC shall coin- cide with DF , because the angle BAC is equal to the angle EDF ; wherefore also the point C shall coincide with the

**point F**... Page 10

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**point F**, and from AE the greater , cut 3. 1. off AG equal a to AF , the less , and join FC , GB . Because AF is equal to AG , and AB to AC , the two sides FA , AC are equal to the two GA , AB , each to each ; and they contain the augle ... Page 12

... point B be on E , and the straight line BC upon EF ; the point C shall also coincide with the

... point B be on E , and the straight line BC upon EF ; the point C shall also coincide with the

**point F**. Because BC is equal to EF ; therefore BC coinciding with 12 THE ELEMENTS. Page 15

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**F**, G ; and bisect FG in H , and join CF , CH , CG ; the 10. 1 . straight line CH , drawn from the given**point**C , is per- pendicular to the given straight line AB . e Because FH is equal to HG , and HC common to the two triangles FHC ...### Other editions - View all

### Common terms and phrases

ABC is given AC is equal altitude angle ABC angle BAC base BC bisected BOOK XI centre circle ABCD circumference common logarithm cone cylinder demonstrated described diameter drawn equal angles equiangular equimultiples Euclid excess fore given angle given in magnitude given in position given in species given magnitude given ratio given straight line gnomon greater join less Let ABC logarithm meet multiple opposite parallel parallelogram AC perpendicular point F polygon prism proportionals proposition pyramid Q. E. D. PROP radius rectangle CB rectangle contained rectilineal figure remaining angle right angles segment side BC similar sine solid angle solid parallelopipeds square of AC straight line AB straight line BC tangent THEOR third triangle ABC triplicate ratio vertex wherefore

### Popular passages

Page 3-7 - IF a straight line be divided into any two parts, the square of the whole line is equal to the squares of the two parts, together with twice the rectangle contained by the parts.

Page 16 - Any two sides of a triangle are together greater than the third side.

Page 26 - Therefore all the angles of the figure, together with four right angles, are equal to twice as many right angles as the figure has sides.

Page 16 - If, from the ends of the side of a triangle, there be drawn two straight lines to a point within the triangle, these shall be less than, the other two sides of the triangle, but shall contain a greater angle. Let...

Page 304 - Again ; the mathematical postulate, that " things which are equal to the same are equal to one another," is similar to the form of the syllogism in logic, which unites things agreeing in the middle term.

Page 4 - DL is equal to DG, and DA, DB, parts of them, are equal ; therefore the remainder AL is equal to the remainder (3. Ax.) BG : But it has been shewn that BC is equal to BG ; wherefore AL and BC are each of them equal to BG ; and things that are equal to the same are equal to one another ; therefore the straight line AL is equal to BC.

Page 147 - If two triangles have one angle of the one equal to one angle of the other and the sides about these equal angles proportional, the triangles are similar.

Page 3-16 - To divide a given straight line into two parts, so that the rectangle contained by the whole, and one of the parts, may be equal to the square of the other part.

Page 159 - SIMILAR triangles are to one another in the duplicate ratio of their homologous sides.