| Mathematics - 1801 - 446 pages
...EXAMPLES. I. Multiply 123456789 by 25. 123456789 617283945 5 ..3086419725 the Product. 2. Multiply * The reason of this method is obvious ; for any number multiplied by the component parts of another number must give the same product, as though it were multiplied by that number at once : thus in example... | |
| Samuel Webber - Mathematics - 1808 - 466 pages
...reason of this method is obvious ; for any number, multiplied by the component parts of another number, must give the same product, as if it were multiplied by that number at once ; thus, in example the second, 7 times the- product of 8, multiplied into the given number,... | |
| Charles Hutton - Mathematics - 1811 - 406 pages
...2873208688 * The reason of this rule is obvious enough ; for any number multiplied by the component pans of another, must give the same product as if it were multiplied by that number at once Thus, in the 1st example, 7 times the product of « by the given number, snakes 56 times the... | |
| Samuel Webber - Arithmetic - 1812 - 260 pages
...draw a curved line, and write the divisor on the left, and the quotient, as it rises, on the right. give the same product, as if it were multiplied by that number at once ; thus, in example the second, 7 times the product of 8, multiplied into the given number,... | |
| Charles Hutton - Mathematics - 1812 - 620 pages
...by 56, or 7 times 8. 5J307298 7 359151086 8 2873208688 * The reason of this rule is obvious enough; for any number multiplied by the component parts of another, must give tbe same produo as if it were multiplied by iliai number at once. Thus, in Uie 1st example, 7 times... | |
| Charles Hutton - Arithmetic - 1818 - 646 pages
...50, or 7 times 8. 51307298 7 359161086 8 2873208688 • The reason of this rule ii obvious enough ; for any number multiplied by the component parts of another, must give the same proiluct as if it were multiplied by that number at once. Tluis, in the 1st example, 7 times the product... | |
| Nicolas Pike - Arithmetic - 1832 - 538 pages
...and that product by the other, ic. and the last product wilLbe the total required.* • The reafon of this method is obvious : For any number, multiplied by the component parts of another number, muft give the fame producft, ai though it were multiplied by that number at once: Thus, in... | |
| Charles Hutton - Mathematics - 1825 - 608 pages
...359151086 2873208688 * The reason of this rule is obvious enough ; for any number multiplied by i he component parts of another, must give the same product as if it were multiplied by that number at once. Thus, in the 1st example, 7 times the product of 8 by the given number, nrnkp.s 56 times the... | |
| Nicolas Pike, Dudley Leavitt - Arithmetic - 1826 - 214 pages
...right of a number increases the value of that number in a tenfold proportion. t The reason of this rule is obvious; for any number multiplied by the component...same product as if it were multiplied by that number at once. 40. What is the rule when the multiplier is 10, 109, 1009, Sfc. ? £1. Whtn th< multiplier... | |
| Charles Hutton - Mathematics - 1831 - 632 pages
...2142273888. Ans. 684323328. Ans. 17326526400. Ans. 81623150400. * The reason of this rule is obvious enough ; for any number multiplied by the component parts of...same product as if it were multiplied by that number at once. Thus, in the 1st example, 7 times the product of 8 by the given number, makes 56 times the... | |
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