| Oliver Welch - Arithmetic - 1812 - 236 pages
...to add in the lowest denomination mentioned; find the sum o£ that denomination ; divide that sum by the number which it takes of this denomination, to make one of the next higher ; set down the remainder, and carry the quotient to the next denomination ; find the sum of the next... | |
| Oliver Welch - Arithmetic - 1857 - 244 pages
...lowest denomination mentioned ; find the sum of that denomination ; divide the sum by the numberwhich it takes of this denomination, to make one of the next higher 5 set down the remainder, and carry the quotient to the next denomination ; find the sum of the next... | |
| Silvestre François Lacroix - Arithmetic - 1821 - 160 pages
...numerator by 20, or dividing the denominator by this number, gives ||*. or 2-/1 s- <"' 2s. 9d. From tbe above example we may deduce the following general...terms, and the last sum will be the fraction required). Tofind the value of a fraction of a higher denomination in terms of a lower, multiply the numerator... | |
| Leonard Pierce - Arithmetic - 1823 - 170 pages
...by reducing the given number to the lowest denomination mentioned, for a numerator, and placing that number which it takes of this denomination to make one of the next higher, for a denominator. In the example before given, 2 Ib. 6 oz. 16 pwt. 12 gr. if you wi«h to reduce it... | |
| Silvestre François Lacroix - Arithmetic - 1825 - 168 pages
...different denominations. If we multiply it by 37, we shall have £4ff is» or £l77JT\ ; and £¥VT, reduced to shillings by multiplying the numerator...denominator of this sum by so many as make one of the next denonination, and so on through all t]ie terms, and the last sum will be the fraction required,^ To... | |
| Silvestre François Lacroix - Arithmetic - 1825 - 394 pages
...shillings by multiplying the numerator by 20, or dividing the denominator by this number, gives a|s. or 2T\s. or 2s. 9d. From the above example we may...denominator of this sum by so many as make one of the next denonination, and so on through all the terms, and the last sum will be the fraction required.] To... | |
| Martin Ruter - Arithmetic - 1831 - 190 pages
...each other. Add the figures of the first column or denomination together, and divide the amount by the number which it takes of this denomination to make one of the next higher. Set down the remainder, and carry the quotient to the next denomination. Find the sum of the next column... | |
| Arithmetic - 1841 - 200 pages
...in the lowest denomination mentioned; (6) find the sum of that denomination, divide the • sum by the number which it takes of this denomination to make one of -the next higher, set down the remainder, and carry the quotient to the next denomination ; (6| find the sum of the next,... | |
| James Bates Thomson - Arithmetic - 1846 - 362 pages
...required. II. To reduce compound Nos. to higher denominations. Divide the given denomination by that number which it takes of this denomination to make ONE of the next higher. Proceed in this manner with each successive denomination, till you come to the one required. The last... | |
| James Bates Thomson - Arithmetic - 1846 - 354 pages
...required. II. To reduce compound Nos. to higher denominations. Divide the given denomination by that number which it takes of this denomination to make ONE of the next higher. Proceed in this manner with each successive denomination, till you come to the one required. The last... | |
| |