 | John Wallace - Steam engineering - 1865 - 432 pages
...centre of the shaft. There is also a circle described on the centre of the shaft, with a radius equal to the distance from the centre of the shaft to the centre of the crank wrist. Now. it will be seen, that the time occupied by the piston in the last half of its... | |
 | Joseph Lawrence - 1867 - 64 pages
...to one edge for the crank pin. The stroke of the piston being one inch, the throw of the crank, or the distance from the centre of the shaft to the centre of the crank pin, must be 5 inch. It may be taken as a rule that the throw of the crank is always equal... | |
 | Samuel Edward Warren - Machine design - 1870 - 376 pages
...the two or more pillow-blocks on the same shaft into line ; or, in case of a steam engine, to adjust the distance from the centre of the shaft to the centre of the cylinder. The pillow-block shown in the figure, being for a 14" horizontal shaft, the bearings,... | |
 | Charles Augustus Smith - Steam engineering - 1885 - 326 pages
...of the steam to each end of tho cylinder. By curvFIG. ing the link to nn arc with a radius equal to the distance from the centre of the shaft to the centre of the slider when the valve is placed in its central position on its seat, this action is removed. In... | |
 | Frederick Arthur Halsey - Slide-valves - 1890 - 178 pages
...the centre of the shaft to the centre of the crank pin, and similarly the "throw" of an eccentric is the distance from the centre of the shaft to the centre of the eccentric disc. Usually the centre of the disc is within the circumference of the shaft; but this... | |
 | Frederick Arthur Halsey - 1894 - 180 pages
...shaft came within the circumference of the pin, the result would be an eccentric. The arm of a crank is the distance from the centre of the shaft to the centre of the cranjc pin, and similarly the " throw" of an eccentric is the distance from the centre of the shaft... | |
 | Charles Herbert Wright - Drawbridges - 1897 - 124 pages
...pressure from the worm-nut in its guides. This is equal to 75 X 60 -7- 8 = 562.5 Ibs. (Eight inches being the distance from the centre of the shaft to the centre of bearing of the nut on its guides.) Forces causing friction on the bearings are then 120 + 45 + 562.5... | |
 | Charles Herbert Wright - Drawbridges - 1897 - 140 pages
...pressure from the worm-nut in its guides. This is equal to 75 X 60 -T- 8 = 562.5 Ibs. (Eight inches being the distance from the centre of the shaft to the centre of bearing of the nut on its guides.) Forces causing friction on the bearings are then 120 + 45 + 562.5... | |
 | Frederick Arthur Halsey - Slide-valves - 1898 - 252 pages
...shaft came within the circumference of the pin, the result would be an eccentric. The arm of a crank is the distance from the centre of the shaft to the centre of the crank pin, and similarly the " throw" of an eccentric is the distance from the centre of the shaft... | |
 | Andrew Jamieson - Mechanics, Applied - 1903 - 584 pages
...from •0196 with a load of 20 Ibs. per square inch at 50 revolutions per minute it fell to .0107 • It is worthy of mention that two opposite radial grooves...to be 1 inch from the centre of the shaft, we have : — FRICTION OF A PIVOT BEARING. at 353 revolutions per minute with the same load ; and from ,0221... | |
| |
It is worthy of mention that two opposite radial grooves were found to act better than three or four or any other number. t The true leverage of the chain is the actual leverage divided by the distance from the centre of the shaft to the centre of frictional... 
