| Charles Hutton - Arithmetic - 1766 - 191 pages
...and the debt is 135/. 4*. P«QPROBLEM VI. Given the extremes a'nd the common difference, to find 1 . **The number of terms. RULE. Divide the difference of the extremes by the common difference,** add i to the quotient, and the fum }vill be the number of terms. 2. The fum of the feries. Having found... | |
| John Mair - Arithmetic - 1772 - 376 pages
...extremes, and common difference, to find the number of terms 5 that is, given I. II. IV. to End III. **RULE. Divide the difference of the extremes by the common difference, and the** quot plus unity is the number of terms, by Theorem IV. EXAMPLE I. A fetting out on a journey, travels... | |
| Mathematics - 1801 - 426 pages
...fast term, the last term, and the common dIfference, to Jind the number of Serins. P.U1.E.* . jpivide **the difference of the extremes by the common Difference, and the quotient,** increased by i, is the number of terms required. . ~" EXAMPLES. * By the last problem,' the difference... | |
| Nicolas Pike - Arithmetic - 1802 - 352 pages
....iboo+i X 1000 " / =500500 Anfwer. 2 PROBLEM 3. Given the extremis and the common dtffsr~ fnce, to Jind **the number of terms. RULE. — Divide the difference...EXAMPLES. I. The extremes are 3 and 39, and the common** difference 2 ; what is the number of terms ? t Ч * • ' «* 3' £ Extremes. ^P ' • Common differences:... | |
| William M. Finlay - Accounting - 1803 - 276 pages
...36-7-18=2 common dif. PROBLEM V. Given the first term, the last term, and common difference, to find **the number of terms. RULE.— •Divide the difference of the extremes by the common difference—** Jhe quotient + lj "»ñu be the number of terms required. EXAMPLE. Given the first, 7 the last, S l... | |
| Thomas Hodson - Arithmetic - 1806 - 492 pages
...2 is the common difference. PROBLEM II. Having the two extremes and the common difference, to find **the number of terms. Rule. Divide the difference of the extremes by the** com- VOL. I. li own mon difference, and i added to the quotient will be the number of terms. Example... | |
| Samuel Webber - Mathematics - 1808 - 470 pages
...distance 366 miles. PR0BLEM III. Given thefirst term, the last term, and the common difference^ tofmd **the number of terms. RULE.* Divide the difference...extremes by the common difference, and the quotient,** increased by 1, is the number of terms required. * By the last problem, the difference of the extremes,... | |
| American - Arithmetic - 1811 - 216 pages
...ftrike in 12 hours ? extremes 1+- 12=13,x (i 12=) 6=78 A. 2; or 1н- 12=13 x 12=150(78 times. A. RULE 2. **Divide the difference of the extremes by the common difference, and the quotient increafed by** one is the number of terms. Ex. if a man gave his youngeft fon 400 S, the next 630, &c. increafing... | |
| Jeremiah Joyce - Arithmetic - 1812 - 276 pages
...III. The extreme terms a and z, and common difference d being given, to find the number of terms n. **RULE. Divide the difference of the extremes by the common difference, and the quotient** increased by unity is the number sought : or + i ~ n. Ex. 1. When the extremes are 4 and 106, and the... | |
| Samuel Webber - Arithmetic - 1812 - 266 pages
...distance 366 miles. PROBLEM 3. Given the first term, the last term, and the common difference^ to find **the number of terms. % RULE.* Divide the difference of the extremes by the common** dlf* By the last problem, the difference of the extremes, divided by the number of terms less 1, gives... | |
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