If two chords intersect within a circle, the product of the segments of one is equal to the product of the segments of the other. Plane Geometry - Page 148by Arthur Schultze - 1901Full view - About this book
| Robert Fowler Leighton - 1880 - 428 pages
...the quadrilateral. 6. If two chords intersect within the circle, the product of the segments of the one is equal to the product of the segments of the other. Prove. What does this proposition become when the chords are replaced by secants intersecting without... | |
| Edward Albert Bowser - Geometry - 1890 - 420 pages
...Proposition 29. Theorem. 335. If two chords cut each other in a circle, the product of the segments of the one is equal to the product of the segments of the other. Hyp. Let the chords AB, CD cut at P. To prove AP X BP = CP x DP. Proof. Join AD and BC. In the AS APD, CPB,... | |
| Rutgers University. College of Agriculture - 1893 - 680 pages
...the intercepted arcs. 4. If two chords cut each other in a circle, the product of the segments of the one is equal to the product of the segments of the other. 5. The area of a triangle is equal to half the product of its base and altitude. 6. The areas of si... | |
| George Albert Wentworth, George Anthony Hill - Geometry - 1894 - 150 pages
...intersect at E, prove that AE = ED and BE = EC. 6. If any two chords are drawn through a fixed point in a circle, the product of the segments of one is equal to the product of the segments of the other. middle point of BC, prove that EF produced bisects AD. 8. Two similar triangles are to each other as... | |
| George D. Pettee - Geometry, Plane - 1896 - 272 pages
...any other and its external segment. Dem. AB x AD = AC x AE [= AF * ] PROPOSITION XXIII 220. Theorem. If two chords intersect within a circle, the product of the segments of one equals the product of the segments of the other. Dem. x = Y A=D &AEC DEB AE:CE=DE: BE AE x BE = CE... | |
| James Howard Gore - Geometry - 1898 - 232 pages
...to that side. PROPOSITION XVIII. THEOREM. 229. If any tiuo chords are drawn through a fixed point in a circle, the product of the segments of one is equal to the product of the segments of the other. Let AB and A'B' be any two chords of the circle ABB' passing through the point P. To prove that Ap... | |
| George Albert Wentworth - Geometry, Modern - 1899 - 272 pages
...first. Then Iff - AC* = 2 BC X MD. Q . E . D PROPOSITION XXXII. THEOREM. 378. If two chords intersect in a circle, the product of the segments of one is equal to the product of the segments of the other. Let any two chords MN and PQ intersect at 0. To prove that OM X ON= OQ X OP. Proof. Draw HP and NQ.... | |
| George Albert Wentworth - Geometry - 1899 - 500 pages
...first. Then AB* - AC* = 2 BC X MD. i,. E . D PROPOSITION XXXII. THEOREM. 378. If two chords intersect in a circle, the product of the segments of one is equal to the product of the segments of the other. Let any two chords MN and PQ intersect at 0. To prove that OM X ON = OQ X OP. Proof. Draw MP and NQ.... | |
| Arthur Schultze, Frank Louis Sevenoak - Geometry - 1901 - 394 pages
...then Off — O'-D 2 = Off — O'C*. * Ex. 631. Conversely, if, in the same diagram, D be taken so that then the tangents drawn from any point in the perpendicular,...Hyp. The chords AB and CD meet in E. To prove AE x Eli = CE x ED. HINT. — What is the means of proving that the product of two lines is equal to the... | |
| Alan Sanders - Geometry, Modern - 1901 - 260 pages
...contact into segments whose product is equal to the square of the radius. PROPOSITION XXII. THEOREM 528. If two chords intersect within a circle, the product...equal to the product of the segments of the other. Let the chords AB and CD intersect at E. To Prove AE . ER = CE • ED. Proof. Draw AC and DB. Prove... | |
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