First Part of an Elementary Treatise on Spherical Trigonometry |
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Page 3
of the planes BOC and AOC is equal to the angle ( 428 ) C , that is , to a right angle ; these two planes are , therefore , perpendicular to each other . Moreover , the angle BOA , measured by BA , is equal to B A or h ; BOC is equal to ...
of the planes BOC and AOC is equal to the angle ( 428 ) C , that is , to a right angle ; these two planes are , therefore , perpendicular to each other . Moreover , the angle BOA , measured by BA , is equal to B A or h ; BOC is equal to ...
Page 26
De- Fig.4 note by a , b , c , the sides respectively opposite to the angles A , B , C. A From either of the vertices let fall the perpendicular BP upon the opposite side AC . Then , in the right triangle ABP , making BP the middle part ...
De- Fig.4 note by a , b , c , the sides respectively opposite to the angles A , B , C. A From either of the vertices let fall the perpendicular BP upon the opposite side AC . Then , in the right triangle ABP , making BP the middle part ...
Page 27
If , in a spherical triangle , two right triangles are formed by a perpendicular let fall from one of its verticles upon the opposite side ; and if , in the two right triangles , the middle parts are so taken that the perpendicular is ...
If , in a spherical triangle , two right triangles are formed by a perpendicular let fall from one of its verticles upon the opposite side ; and if , in the two right triangles , the middle parts are so taken that the perpendicular is ...
Page 28
If the perpendicular is an opposite part in both the triangles , we have , by ( 475 ) , ( 611 ) sin . M = cos . O cos . P , ( 612 ) sin . m = cos . O cos . p . The quotient of ( 611 ) divided by ( 612 ) is sin . M cos .
If the perpendicular is an opposite part in both the triangles , we have , by ( 475 ) , ( 611 ) sin . M = cos . O cos . P , ( 612 ) sin . m = cos . O cos . p . The quotient of ( 611 ) divided by ( 612 ) is sin . M cos .
Page 29
PA :: cotan . C : cotan . BAP , ( 618 ) and BAP is the angle A ( fig . 4. ) , when the perpen- ( 619 ) dicular falls within the triangle ; or it is the supplement of A ( fig . 5. ) , when the perpendicular falls without the triangle .
PA :: cotan . C : cotan . BAP , ( 618 ) and BAP is the angle A ( fig . 4. ) , when the perpen- ( 619 ) dicular falls within the triangle ; or it is the supplement of A ( fig . 5. ) , when the perpendicular falls without the triangle .
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First Part of an Elementary Treatise on Spherical Trigonometry (Classic Reprint) Benjamin Peirce No preview available - 2017 |
First Part of an Elementary Treatise on Spherical Trigonometry Benjamin Peirce No preview available - 2016 |
Common terms and phrases
A'BC acute adjacent angles angles are given becomes calculated called Corollary corresponding cosec cosine cotan deduced Demonstration denote determined differs divided equal to 90 equation EXAMPLES expressions factor fall on AC Fourthly fractions given angle gives greater than 90 half the sum hemisphere Hence hypothenuse impossible included angle known leads legs Lemma less than 90 Let ABC fig let fall logarithm lunary surface measured middle negative numerator obtained obtuse opposite angle opposite side perpendicular perpendicular BP positive preceding Problem proportion proved quantity quotient reduce result right angle Rules satisfy Scholium second member Secondly sides and angles sides equal signs sine Solution solve a spherical solve the triangle spherical right triangle spherical triangle ABC substituted supplements surface ABC tang tangent of half Theorem Thirdly tive trian triangle ABC figs whence
Popular passages
Page 69 - The areas of two triangles which have an angle of the one equal to an angle of the other are to each other as the products of the sides including the equal angles. D c A' D' Hyp. In triangles ABC and A'B'C', ZA = ZA'. To prove AABC = ABxAC. A A'B'C' A'B'xA'C' Proof. Draw the altitudes BD and B'D'.
Page 1 - A spherical triangle is a portion of the surface of a sphere, bounded by three arcs of great circles.
Page 69 - THEOREM. The surface of a spherical triangle is measured by the excess of the sum of its three angles above two right angles, multiplied by the tri-rectangular triangle.
Page 8 - I. The sine of the middle part is equal to the product of the tangents of the adjacent parts.
Page 8 - II. The sine of the middle part is equal to the product of the cosines of the opposite parts.
Page 30 - Any angle is greater than the difference between 180° and the sum of the other two angles.
Page 51 - The cosine of half the sum of two sides of a spherical triangle is to the cosine of half their difference as the cotangent of half the included angle is to the tangent of half the sum of the other two angles.
Page 51 - The cosine of half the sum of two angles of a spherical triangle is to the cosine of half their difference as the tangent of half the included side is to the tangent of half the sum of the other two sides.
Page 71 - ... and the sum of the angles in all the triangles is evidently the same as that of all the angles of the polygon ; hence, the surface of the polygon is equal to the sum of all its angles, diminished by twice as many right angles as it has sides less two, into the tri-rectangular triangle.